Now a days, we are surrounded by lies all the time. But if we look close enough, we will always find exactly one truth for each matter. In this task, we will try to put that truth in the middle. Let's say we have a n x n matrix (n> 1 and must be an odd number), consisting of n^2 - 1 false statements and a single true statement. Let's index the matrix rows by numbers from 1 to n from top to bottom, let's index the matrix columns by numbers from 1 to n from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix: • Swap two neighboring rows, that is, rows with indexes i and i + 1 for some integer i (1 ≤i

Now a days, we are surrounded by lies all the time. But if we look close enough, we will always find exactly one truth for each matter. In this task, we will try to put that truth in the middle. Let's say we have a n x n matrix (n> 1 and must be an odd number), consisting of n^2 - 1 false statements and a single true statement. Let's index the matrix rows by numbers from 1 to n from top to bottom, let's index the matrix columns by numbers from 1 to n from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix: • Swap two neighboring rows, that is, rows with indexes i and i + 1 for some integer i (1 ≤i

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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You will be given a square matrix of N rows and N columns (1 <= N <= 1000) containing positive and negative integers with absolute value not larger than 1000. You are required to compute the greatest sum achievable by walking a path, starting at any cell of the matrix and always moving downwards or rightwards. Additionally, you have to report the number of times that value is achievable. N will be in the first line of the input. N lines follow with N integers each. You should output a single line with two integers separated by a single blank space: first one is the greatest sum, second one is the number of times this value can be reached.
you will be given a square matrix of N rows and N columns (1 <= N <= 1000) containing positive and negative integers with absolute value not larger than 1000. You are required to compute the greatest sum achievable by walking a path, starting at any cell of the matrix and always moving downwards or rightwards. Additionally, you have to report the number of times that value is achievable. N will be in the first line of the input. N lines follow with N integers each. You should output a single line with two integers separated by a single blank space: first one is the greatest sum, second one is the number of times this value can be reached. Case 1: For the input provided as follows: 53 1 -2 1 1-6 -1 4 -1 -41 1 1 1 12 2 2 2 21 1 1 1 1 Output of the program will be: 15 1 Case 2: For the input provided as follows: 31 1 12 2 23 3 3 Output of the program will be: 12 1
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Create a row vector of 1's that has 4 rows. Now Create a column vector of 1's that has 4 columns. Using matrix multiplication, multiply both of these to get a 4x4 matrix and display the resulting matrix. Using matlab, do this. Please answer it correctly and don’t copy from anywhere otherwise it will be downvoted.
Hendy wants to find the transpose of a 2 d matrix. You can assume the matrix as your own and order must be 3x3 and print it. Write a java program for that.
Nine coins are placed in a 3x3 matrix with some face up and some face down. You can represent the state of the coins using a 3x3 matrix with values 0 (heads) and 1 (tails). Here are some examples:0 0 0 1 0 1 1 1 00 1 0 0 0 1 1 0 00 0 0 1 0 0 0 0 1Each state can also be represented using a binary number. For example, the preceding matrices correspond to the numbers:000010000 101001100 110100001There are a total of 512 possibilities, so you can use decimal numbers 0, 1, 2, 3,...,511 to represent all the states of the matrix. Write a program that prompts the user to enter a number between 0 and 511 and displays the corresponding matrix with the characters H and T.
Write a program that inputs a matrix and displays the trans- pose of that matrix. A transpose of a matrix is obtained by converting all the rows of a given matrix into columns and vice versa.
A matrix is an array of numbers of size m by n (i.e., m x n). When we multiply 2 matrices, we multiply the matching numbers, then sum them up. Multiplying a matrix of size m x n with another matrix of size n x q will result in a matrix of size m x q. An example is shown in Figure 1: [ ? ? ? ? ? ? ] x [ ? ? ? ? ] = [ ?? +?? ?? + ?? ?? + ?? ?? + ?? ?? + ?? ?? + ?? ] Matrix 3 x 2 Matrix 2 x 2 Matrix 3 x 2 Figure 1: Multiplication of Matrix 3 x 2 and 2 x 2 Write a C++ program that multiplies 2 matrices and return the sum of the transposed matrix. Your program shall include the following: a) Define two 2 dimensional arrays, M and N that each represents a matrix of size 3 x 2 and a matrix of size 2 x 2. Request the user to enter the values for the 2 arrays using advanced pointer notations (refer to your slides for the list of array pointer notations). b) Create a function named multMatrix() that passes as arguments, the values of array M and N, multiplies them and store the results in a new…
Recall that np.dot (a,b) performs a matrix multiplication on a and b, whereas ab performs an element-wise multiplication. Consider the two following random arrays "a" and "b": a = np.random.randn (12288, 150) a.shape (12288, 150) b = np.random.randn(150, 45) b.shape= (150, 45) c = np.dot (a, b) What is the shape of c?
Given a matrix of m x n elements (m rows, n columns),return all elements of the matrix in spiral order.For example,Given the following matrix:[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ]]You should return [1,2,3,6,9,8,7,4,5].""" def spiral_traversal(matrix): res = [] if len(matrix) == 0: return res row_begin = 0 row_end = len(matrix) - 1 col_begin = 0 col_end = len(matrix[0]) - 1 while row_begin <= row_end and col_begin <= col_end: for i in range(col_begin, col_end+1): res.append(matrix[row_begin][i]) row_begin += 1 for i in range(row_begin, row_end+1): res.append(matrix[i][col_end]) col_end -= 1 if row_begin <= row_end: for i in range(col_end, col_begin-1, -1): res.append(matrix[row_end][i]) row_end -= 1 if col_begin <= col_end: for i in range(row_end, row_begin-1, -1): res.append(matrix[i][col_begin]) col_begin += 1