Three small spheres of mass M are fastened to each other by three identical rods of mass m and length L, as shown in the figure. Determine themoment of inertia of the system by treating the spheres as point particles. (For rods ICM = (mL²)/(12)).MLmLMMRadi-RasmussenSelect one:O a. I =(M + ) L²O b. I = (3M +m)L²O c. I =(3M + ) L²d. I = (3M + ™) L²(블+ ) L?O f. I = (M + ) L²(М-+3т)L?O h. I = (M + ) L²O e. I =O g. I =

Given: To find the moment of inertia is calculated shown as:

Answered: nass m and lengt CM = (mL³)/(1-

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nass m and lengt CM = (mL³)/(1-

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter10: Fixed-axis Rotation

Section: Chapter Questions

Problem 112AP: A system of point particles is rotating about a fixed axis at 4 rev/s. The particles are fixed with...

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