Na₂CO3(aq) +CaCl₂ (aq) → 2 NaCl(aq) + CaCO3(s) Calculate the volume (in mL) of 0.200 M CaCl₂ needed to produce 2.00 g of CaCO3(s) There is an excess of Na₂CO3. Molar mass of calcium carbonate = 100.09 g/mol Volume of calcium chloride = 100.0 mL

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.