n= 6-n = 5 Express the frequency in inverse seconds.

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter19: Nuclear Magnetic Resonance Spectroscopy
Section: Chapter Questions
Problem 19.14QAP: What is a rotating frame of reference?
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Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions.

• Part D
n = 6n = 5
Express the frequency in inverse seconds.
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Transcribed Image Text:• Part D n = 6n = 5 Express the frequency in inverse seconds. ΑΣφ Submit Request Answer
Expert Solution
Step 1

In hydrogen spectrum, when an electron is jumped from higher energy level to lower energy level then frequency is given by below formula.

ν=c×Rh×1n12-1n22

Where c is speed of light, Rh is Rydberg constant, n1 and n2 are natural numbers but n2 is always greater than n1.

 

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