A 2 kg particle is acted on by a force as shown in the image below. The particle has an initial velocity vector (before the force is applied) of ₁ = 4 + 3) m/s and a final velocity vector (after the force is applied) of ₂ = -21+ 6) m/s. The force is applied for 3 s. a. Determine the impulse that has acted on the particle b. Determine the average force applied and its angle c. The net work done by the force acting on the particle (No change in particle height) Note: The image shown below is a top-down view of the particle and force. F X

Physics for Scientists and Engineers: Foundations and Connections
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Chapter11: Collisions
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A 2 kg particle is acted on by a force as shown in the image below. The particle has an initial
velocity vector (before the force is applied) of ₁ = 4 + 3) m/s and a final velocity vector (after the
force is applied) of ₂ = -21+ 6) m/s. The force is applied for 3 s.
a. Determine the impulse that has acted on the particle
b. Determine the average force applied and its angle
c. The net work done by the force acting on the particle (No change in particle height)
Note: The image shown below is a top-down view of the particle and force.
F
X
Transcribed Image Text:A 2 kg particle is acted on by a force as shown in the image below. The particle has an initial velocity vector (before the force is applied) of ₁ = 4 + 3) m/s and a final velocity vector (after the force is applied) of ₂ = -21+ 6) m/s. The force is applied for 3 s. a. Determine the impulse that has acted on the particle b. Determine the average force applied and its angle c. The net work done by the force acting on the particle (No change in particle height) Note: The image shown below is a top-down view of the particle and force. F X
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