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- 2 MnO4- (aq) + 5 C2O42- (aq) + 16 H+ (aq) « 2Mn2+ (aq) + 10 CO2 (g) + 8 H2O(l) 0.4040 g of the unknown compound (K2Zy(C2O4)z . nH2O) was dissolved in 100.0 mL water to make a solution. It was then heated to 80oC and titrated with a KMnO4 solution as shown below: The molarity of KMnO4 = 0.0.02321 M Volume used = 29.25 mL A.) What is the % Oxalate by mass for the unknown solid titrated?2 Ba2+ (aq) + Cr20,2 (aq) + H2O (I) 2 BaCro4 (s) + 2 H* (aq) Dichromate forms orange aqueous solutions and barium chromate is a white solid. Ba(NO3)2 is placed into a test tube of aqueous K2Cr207 forming a colorless solution with a noticeable amount of white solid at the bottom. Use Le Chatelier's Principles to answer the following questions. A. What would you expect to observe if HC was added to the test tube? Explain why the expected observation occurred. B. What could you add to the test tube to increase the amount of solid that would form? Explain why you chose that substance. C. You cool the test tube and notice an increase in the amount of solid formed in the solution. Explain what that suggests about the above reaction?MeONa NaN 7 Fe 7 Sn N.
- Gold can be determined in solutions containing high concentrations of diverse ions by ICP-AES. Aliquots of 50.0 mL of the sample solution were transferred to each of four 100.0 mL volumetric flasks. A solution was prepared containing 10.0 mg/L Au in 20% H2SO4 and quantities of this solution were added to the sample solutions to give 0, 2.5, 5, and 10 mg/L added Au in each of the flasks. The solutions were made up to a total volume of 100.0 mL, mixed, and analysed by ICP-AES. The resulting data are presented in the following table. Added Au, mg/L Emission Intensity Count 12,568 19,324 26,622 40,021 0.0 2.5 5.0 10.0 Calculate the concentration of gold in the original sample.Cr(NO3)3 C. Show HintGold can be determined in solutions containing high concentrations of diverse ions by ICP. Aliquots of 50.0 mL of the sample solution were transferred to each of four 100.0 mL volumetric flasks. A solution was prepared containing 10.0 mg/L Au in 20% H2SO4, and quantities of this solutions were added to the sample solution to give 0, 2.5, 5 and 10 mg/L added Au in each of the flask. The solutions were made up to a total volume of 100.0 mL, mixed and analyzed by ICP. The resulting data are presented in the following table: Added Au (mg/L) Emission Intensity (Counts) 0.0 12568 2.5 19324 5.0 26622 10.0 40021 a) Attach an excel graph for the determination showing the X intercept. b) Calculate the concentration of gold in the sample, report with its uncertainty. c) The known concentration of gold in the sample is 8.51 mg/L. Test the hypothesis that your result is equal to this value at the 95% confidence level. l
- A spectrophotometric method for the analysis of iron has a linear calibration curve for standards of 0.00, 5.00, 10.00, 15.00, and 20.00 ppm. An iron ore sample with an expected iron content of 40–60% w/w is to be analyzed by this method. An approximately 0.5-g sample is taken, dissolved in a minimum of concentrated HCl, and diluted to 1 L in a volumetric flask using distilled water. A 5.00-mL aliquot is removed with a pipet. To what volume (10, 25, 50, 100, 250, 500, or 1000 mL) should it be diluted to minimize the uncertainty in the analysis? Explain.Nick and Kel reacted 2.80g of NiCl2 x 6H20 with 7.00 ml of 4.00 M C2H8N2. They recovered 2.40g of product, [Ni(C2H8N2)3] Cl2. At the end, the filtrate was a dark blue solution. The litmus test on the filtrate solution left the red litmus paper unchanged in color. - NiCl2 x 6H2O + 3C2H8N2 yields [Ni(C2H8N2)3] Cl2(s) + 6H20 - Molor mass of NiCl2 x 6H20 is 237.69 g/mol - Molarity of C2H8N2 is 4.00 M - Molor mass of product,[Ni(C2H8N2)3] Cl2(s) is 309.90 g/mol based on the experiment described, what are answers for the question below the actual or experimenting yield is __2.40g______ the theoretical yeild is __2.89g___ (can someone show me how to caluculate to get this answer?)4. The %Mn in steel can also be determined spectrophotometrically by oxidizing the manganese to the intensely colored permanganate, MnO4-. Standard solutions of permanganate gave the following absorbances (in a 1 cm cell): ABSORBANCE CONC. OF MnO4 (g/mL) 0.210 1.05 x 10-5 0.315 1.61 x 10-5 0.429 2.21 x 10-5 0.599 2.98 x 10-5 0.801 4.04 x 10-5 The following samples of steel were thoroughly reacted to convert the manganese into permanganate and then diluted to 500.00 mL. WT. OF STEEL (g) ABSORBANCE 0.5886 0.611 0.3498 0.359 0.4555 0.482 Again using Excel, plot the calibration data and calculate the %Mn in the steel.
- Nick and Kel reacted 2.80g of NiCl2 x 6H20 with 7.00 ml of 4.00 M C2H8N2. They recovered 2.40g of product, [Ni(C2H8N2)3] Cl2. At the end, the filtrate was a dark blue solution. The litmus test on the filtrate solution left the red litmus paper unchanged in color. - NiCl2 x 6H2O + 3C2H8N2 yields [Ni(C2H8N2)3] Cl2(s) + 6H20 - Molor mass of NiCl2 x 6H20 is 237.69 g/mol - Molarity of C2H8N2 is 4.00 M - Molor mass of product,[Ni(C2H8N2)3] Cl2(s) is 309.90 g/mol based on the experiment described, what are answers for the question below the actual or experimenting yield is ________ the theoretical yeild is _____Determination of metals in soil by AAS Soil Mass of Soil ppm (mg/L) Concentration of Cu in soil Absorbance 1 1.0101g 0.6545 2 1.0064g 0.6203 3 1.0018g 0.5287 Show the calculation on how to calculate the ppm and the concentration of copper in the sample (soil). (The final volume is 200mL)From the following data calculate the potassium content per tablet in effervescent KCl bicarbonate tablets. Weight of 20 tablets = 35.6751 g Weight of tablet powder taken for assay = 0.1338 g The sample is dissolved in 500 ml of water and then 5 ml of the sample solution is taken and diluted to 100 ml. Weight of KCl used to prepare standard = 0.1912 g The standard was dissolved in 100 ml of water and 5 ml of the standard solution was diluted to 250 ml. The diluted standard solution was used to prepare a calibration series by transferring 0, 5, 10, 15, 20 and 25 ml to 100 ml volumetric flasks and making up to volume. The following readings were obtained for the calibration series: 0, 20.3, 40.1, 60.3, 80.1 and 100. Reading obtained for potassium in the diluted sample solution = 73.9. The answer in the book is 496.2 mg of K, however, I can't get to that answer. Can anyone please help with the step-by-step solution? Thanks!