Maximize p = x subject to x − y ≤ 4 −x + 3y ≤ 4 x ≥ 0, y ≥ 0.

Q: Maximize f = x + 3y subject to x + 4y 0 Rectan

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Q: 2. Maximize. z subject to 2x1 + 3x2 – 4x3 = 3x1 - 2x2 + x3 0, x2 > 0, x3 > 0.

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Q: Maximize subject to: Z = $140×₁ + $150x₂ 8x1 + 2x₂ 40 9x2 + 3x₂ ≤ 120 X1, X₂ ≥0

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Q: Maximize P= 7x+9y Subject to: 2x+ y12 x, y 20

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Q: Maximize p = 4x + 3y subject to −3x + y ≥ 17 x + 5y ≤ 19 x ≥ 0, y ≥ 0. p= X,Y=

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Q: Maximize p = 6x + 5y + 4z subject to x + y + z ≤ 150 x + y + z ≥ 100 x ≥ 0, y ≥ 0, z ≥ 0. p=(x, y,…

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Q: Maximize z = 15x + 15y Subject to 10x + 8y z 190 10x - 14y 2 - 30 x+y s 45 X, y z 0

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Q: x(x – 2)y" + 2(x – 1)y' – 2y = 0

A: Solution: x(x-2)y"+2(x-1)y'-2y=0 Solve using the series method: A linear homogeneous ODE with…

Q: Maximize p = 6x + y + 3z subject to 3x + y < 15 2x + 2y + 2z < 20 x 2 0, y 2 0, z 2 0.

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Q: Maximize f = 3x1 + 6x2+ 8T3 subject to 4x1 + 2x2 + 3r3 0, x2 2 0, r3 0 If no solutions exist enter…

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Q: Maximize P= 4x + 7y subject to 2x + y = 0, y>= 0

A: Hi, Since the method of solving the given problem is not mentioned, herewith, I solve the given…

Q: minimize Z = 8x +212 subject to 2r, - 6x, s 12 5x, + 4x2 40 X1 + 2r, 12 X2 S 6 X1, X2 20

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Q: Maximize 5x+5y subject to  2x+y≤30 x+2y≤24 x,y≥0

A: Let us take P = 5x + 5y, now we can form the tables for the constraint inequalities and then solve…

Q: 10. Maximize f(x, y) = 25 – ² - y² subject to 2x + y = 10

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Q: Maximize Z = 19x1 + 8x2 subject to 9x1 + 16x2 0

A: Consider the given problem.

Q: 2) Maximize z = 7x1 + 2x2 + x3 subject to: x1 + 5x2 + 7x3 <8 X1 + 4x2 + 11x3 s 9 x1 20, x2 20, x3 20…

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Q: Maximize P = 5x + 3y subject to 4x + 2y ≤ 20 3x + 3y ≤ 21 x ≥ 0, y ≥ 0

A: Please see the below explanation:

Q: Maximize Z = 2x1 + x2; Subject to x2 ≤ 10 2x1 + 5x2 ≤ 60 x1 + x2 ≤ 18 3x1 + x2 ≤ 44 and x1 ≥ 0, x2 ≥…

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Q: Maximize p = 9x + 6y subject to x + 3y ≥ 6 −x + y ≤ 4 2x + y ≤ 8 x ≥ 0, y ≥ 0.

A: Max P=44 at (x,y)=(1.33,5.33)

Q: maximize p=x1-x2 subject to x1+x2≤4 2x1+7x2≤14 with x≥0 y≥0

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Q: Maximize P=5x-5y   subject to 2x+y≤30 x+2y≤24 x,y≥0

A: We can use the graphical method to find the maximum value of P for this linear programming problem.

Q: Maximize f (x, y) = x + y subject to g (x, y) = x² + y = 4

A: Given function fx,y=x+y......(1) gx,y=x2+y2=4......(2) Applying the Lagrange multiplier, note that…

Q: 21. Maximize f = 2x + 3y subject to x + 2y < 10 x + y< 7

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Q: Maximize p = 7x + 5y + 6z subject to x + y – z s 12 x + 2y + z 0. (х, у, 2) -(| %3D

A: When a LPP involves more than two variables, the solution for the LPP cannot be found using…

Q: Maximize p = 2x + y subject to x + 2y ≤ 10 −x + y ≤ 8 x + y ≤ 8 x ≥ 0, y ≥ 0

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Q: Maximize z = 2x1 + x2  subject to: x1 + x2 ≤ 71  3x1 + x2 ≤ 175   x1 ≥ 0, x2 ≥ 0

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Q: Maximize p = x + y subject to x + 3y ≤ 8 3x + y ≤ 8 x ≥ 0, y ≥ 0.

A: Solve LINEAR PROGRAMMING Problem by using graphical method

Q: Maximize p = 4x + 12y + 6z + 100 Subject To: 4x + 10у + 7z 0, y > 0, z > 0} x = p = = Z VI VI AI +

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Q: Maximize p = x + 2y subject to x + 4y ≤ 22 4x + y ≤ 13 x ≥ 0, y ≥ 0.

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Q: Con company has total costs cl) = 21000-1Sxt O.YxZ and total renenves iven by eco ミ345¢-0.^xて、find…

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Q: Particular solution of y' = x+xy²/4y, y(1) = 0

A: Given differential equation- y'=x+xy24y   , y(1)=0 We need to find particular solution of the given…

Q: 6- Show that y = xsinx is a solution to y +y 2cosx

A: The given differential equation is: y''+y=2 cos x

Q: 2. Maximize Z = 8x +6 x Subject to: 10x,+ x2s 12 2x1+ 5 x2s 16 X120 HNA

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Q: Maximize: z=5x+y subject to: x-ys3 5x + 3y ≤ 75 x20, y20

A: Given,           Maximise: z=5x+y    subject to:                      x-y≤3…

Q: Maximize p = 3x + 4y subject to 0.2x + 0.2y20.4 X 2 0, y 2 0. (x, y) unbounded

A: Given : LPP       Maximize p=3x+4y subject to                      0.2x+0.2y≥4y≤6x≥0, y≥0 To find :…

Q: 8. Maximize P=3x+2y 2x+ys22 x+3 ys26 XS10 Subject to ys10 X,y20

A: The LPP is given as Max P=3x+2y subject to 2x+y≤22x+3y≤26x≤10y≤10x≥0y≥0 We will solve it by…

Q: maximize f = x + 3y + z subject to x + 4y ≤ 12 3x + 6y + 4z ≤ 48 y + z ≤ 8

A: The given problem is: maximize f = x + 3y + z subject to x + 4y ≤ 12 3x + 6y + 4z ≤ 48 y + z ≤ 8

Q: Minimize z = x, + 2x2 Subject to 2x, + 4x, s 160 X1 – Xz = 30 X12 10 X1, X2 2 0

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Q: Maximize p = x subject to X - y<4 —х + Зу < 4 x 2 0, y 2 0. p = (х, у) %3D

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Q: maximize p:6x+y +32 subiect to 3xty <15 2x+2yt22=20 Y-0 7:0

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Q: Maximize p = 2.1x + 4.1y + 2z subject to 3.1x + 1.2y + z ≤ 5.5 x + 2.3y + z ≤ 5.5…

A: According to the given information it is required to solve the given problem:

Q: Maximize p = 3x + 4y + 2z subject to y + zs 5 x + 2y + zS 5 y + zs 4 x 2 0, y 2 0, z 2 0. Зх + x + p…

A: Query is to maximize p=3x+4y+2zsubject to3x+y+z≤5x+2y+z≤5  x+y+z≤5x, y, z≥0

Q: Maximize B = xy“, where x and y are positive numbers such that x + y = 3. The maximum value of B is

A: To maximize, B=xy2  --(1)Given that x+y2=3   ⇒y2=3-x   substituting in (1)

Q: 6- Show that y = xsinx is a solution to y= + y = 2cosx

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Q: Q2, Maximize the profit P which depends on x-size, y=quality and z= weight of the product Maximize,…

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Q: Maximize f(x,,x,)= 24x, – x' +10x, – x %3D subject to *; 58 X, 54 x, 2 0, x, 20 and

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Q: Maximize z = 5x + 6y %3D subject to: 3x + 2y s 12 x +2 y < 8 y 2 0

A: See attached file for a step by step explanation.

Q: Maximize p = 5x + 7y + 6z subject to x + y + z 100 x 2 0, y 2 0, z > 0. p = (х, у, 2) 3

A: The given constraints are, x+y+z≤150, x+y+z≥100 and x≥0, y≥0, z≥0. Obtain the coordinates x,y,z…

Q: Maximize z = 18x1 + 16x2 Subject to 15x1 + 25x2 < 375 24x1 + 11x2 < 264 X1, X2 2 0 ard

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Q: Maximize P = 2x + 6y subject to x + 2y s 8 2x + ys 10 x, y 2 )

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