PLEASE ANSWER ALL OF THE QUESTIONS ON THE PICTURE, PLEASE. MISTERAVUST. TELUTUI LvyumurinneSummaryA useful method to express a number is in logarithmic format. A logarithm is the exponent that a base must be raised to produce a given number.Mathematically, if base* = y then logbase (y) = x. For example we know that 10² = 100 then the log₁0 (100) = 2. Likewise since 10-²0.01 thenlog₁0 (0.01) = −2. Commonly for a base of 10 the logarithm symbol log is used. Thus for 104 = 10,000 the log₁0 (10,000) = 4.Logarithms are not confined to base 10. For 3² = 9 then log3 (9) = 2. A commonly used scientific base is Euler's number, 2.71828... Logarithms based uponEuler's number are called natural logarithms having the symbol In. Scientific calculators readily calculate both the log and In of numbers.Antilogarithms are the inverse function of a logarithm. If logbase (x) = y then the antilogbase (y) = x. In other words base = x. The antilog(2) = 100.Antilog(-2) = 0.01. Like wise there are antilogarithms for natural logarithms. To determine the antilogartihm of a natural logarithm employ the e* functionon your calculator.Math ExampleCalculate In(74.10).In(74.10) =€7.98Calculate e€7.98Chemistry ExampleA freshly purified 1.8000 g sample of pure 32P decays for 7.000 days. After that time the remaining amount of 32P has a mass of 1.2819 g. What is the decay(rate) constant, in day¯¹, for the radioactive decay of 32 P?-1Rate constant =CheckA freshly purified 2.780 g sample of pure0.2661 year¯¹.-1day ¹g22 Na is22 Na is made in the lab. How many grams of 22 Na remain after 1.150 years? The decay (rate) constant forPreviousNext

ln(74.10) = 4.31 e7.98=2.92×103

Math Example Calculate In (74.10). In(74.10) = Calculate e7.98 €7.98= Chemistry Example A freshly purified 1.8000 g sample of pure 32P decays for 7.000 days. After that time the remaining amount of 32P has a mass of 1.2819 g. What is the decay (rate) constant, in day, for the radioactive decay of 32P? Rate constant = day-1 A freshly purified 2.780 g sample of pure 22 Na is made in the lab. How many grams of 22 Na remain after 1.150 years? The decay (rate) constant for 22 Na is 0.2661 year ¹. 9

Math Example Calculate In (74.10). In(74.10) = Calculate e7.98 €7.98= Chemistry Example A freshly purified 1.8000 g sample of pure 32P decays for 7.000 days. After that time the remaining amount of 32P has a mass of 1.2819 g. What is the decay (rate) constant, in day, for the radioactive decay of 32P? Rate constant = day-1 A freshly purified 2.780 g sample of pure 22 Na is made in the lab. How many grams of 22 Na remain after 1.150 years? The decay (rate) constant for 22 Na is 0.2661 year ¹. 9

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter14: Acids And Bases

Section: Chapter Questions

Problem 23Q: How many significant figures are there in the following numbers: 10.78, 6.78, 0.78? If these were pH...

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