Material from chapter 12, 15 2 NO2 (g) N2O4 (g) a. Is this endothermic or exothermic? AH = -57.23 kJ/mol b. If 5 mols of NO2 react, what is the amount of energy absorbed? 5MON O2=(-57.23Ky/ma).(512)= 143.075 di pele -dipile What intermolecular forces are present in NO2 (g)? C. d. Write the equilibrium constant expression.

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Chapter10: Energy
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Material from chapter 12, 15
2 NO2 (g) → N2O4 (g)
a. Is this endothermic or exothermic?
6.
AH = -57.23 kJ/mol
b. If 5 mols of NO2 react, what is the amount of energy absorbed?
SmoNOa=(-57.23KM).(512)= 143.075
dipele -dipile
С.
What intermolecular forces are present in NO2 (g)?
d. Write the equilibrium constant expression.
How does the equilibrium shift
i. as the temperature is increased?
ii. as more N204 (g) is added?
iii. as the volume is decreased?
e.
Transcribed Image Text:Material from chapter 12, 15 2 NO2 (g) → N2O4 (g) a. Is this endothermic or exothermic? 6. AH = -57.23 kJ/mol b. If 5 mols of NO2 react, what is the amount of energy absorbed? SmoNOa=(-57.23KM).(512)= 143.075 dipele -dipile С. What intermolecular forces are present in NO2 (g)? d. Write the equilibrium constant expression. How does the equilibrium shift i. as the temperature is increased? ii. as more N204 (g) is added? iii. as the volume is decreased? e.
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