PRINTER VERSION1 BACKNEXTChapter 11, Problem 022Your answer is partially correct. Try again.A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector = (2.00 m) i - (3.00 m) j + (2.00 m) k,the force is F = F, i + (7.00 N) j - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m)j + (11.0 N-m) k. Determine FNumberUnitsthe tolerance is +/-2%Click if you would like to Show Work for this question: Open Show WorkQuestion Attempts: UnlimitedSAVE FOR LATERSUBMIT ANSWERm

→r=2i - 3j +2k→F=FXi +7j -6k→ζ=4i+10j+11k

m) î - (3.00 m)} + (2.00 m) k, the force is F = F,i + (7.00 N)} - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m) j + (11.0 N-m) k. Determine F A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2. Number "

m) î - (3.00 m)} + (2.00 m) k, the force is F = F,i + (7.00 N)} - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m) j + (11.0 N-m) k. Determine F A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2. Number "

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter3: Vectors

Section: Chapter Questions

Problem 70PQ

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