Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. E Click the icon to view the data table of strontium-90 amounts. ..... What are the null and altemative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. H 4 SH2 OB. H, H =2 - X More info H > P2 OC. H =2 H, 2 OD. H 2 H >2 City #1 109 City 2 117 The test statistic is (Round to two decimal places as needed) 51 100 85 81 107 110 86 121 The P-value is (Round to three decimal places as needed) 111 101 104 213 149 290 100 327 145 State the conclusion for the test 111 O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. 123 133 O B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater 101 209 O D. Fal to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. E Click the icon to view the data table of strontium-90 amounts. ..... What are the null and altemative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. H 4 SH2 OB. H, H =2 - X More info H > P2 OC. H =2 H, 2 OD. H 2 H >2 City #1 109 City 2 117 The test statistic is (Round to two decimal places as needed) 51 100 85 81 107 110 86 121 The P-value is (Round to three decimal places as needed) 111 101 104 213 149 290 100 327 145 State the conclusion for the test 111 O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. 123 133 O B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater 101 209 O D. Fal to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 4GP
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Transcribed Image Text:Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples
selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean armount of strontium-90 from city #1 residents is greater than the mean amount from
city #2 residents.
E Click the icon to view the data table of strontium-90 amounts.
....
What are the null and altemative hypotheses? Assume that population 1 consists of amounts from city # 1 levels and population 2 consists of amounts from city #2.
< X
OB. Ho H1=42
H: > 2
O A. Ho 4 SH2
More info
OC. Ho =H2
OD. Ho H
H: > 2
City #1
109
City 2
117
The test statistic is. (Round to two decimal places as needed.)
51
100
85
81
86
121
The P-value is (Round to three decimal places as needed.)
111
101
State the conclusion for the test.
104
213
149
290
107
110
111
123
O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
100
133
327
101
O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
145
209
O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
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