Let's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a big-endian computer after executing: uint32_t x = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter12: Points, Classes, Virtual Functions And Abstract Classes
Section: Chapter Questions
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Let's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78.
If p's type is "uint32_t *", what is the value of x on a big-endian computer after executing: uint32_tx = p[0];
Ox01122334
Ox0112233445566778
Ox34231201
Ox7867564534231201
O 0 0 O
Transcribed Image Text:Let's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a big-endian computer after executing: uint32_tx = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O 0 0 O
Expert Solution
Step 1

Big-endian computer, will represent each byte from left to right order.

Little endian will represent each bite from right to left order.

uint32_t can store 32 bits 

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