18:25 Wed Jun 16* 13% Ilab 7...HomeInsertDrawLayoutReviewViewBI U A.Arial12LAB 06 Mole to Mole Relationship between Cu and Ag Lab-procedures-notes-HelpLab ResultsRecord and calculate the following:Trial 1Trial 2Trial 3Mass of the empty beaker(g)Mass of Copper Added to Beaker(g)Mass of Silver and Beaker(g)110.00110.0000.1000.200110.340110.679Clear solution/copper solidLight BleuNote the color BeforeNote the color AfterData AnalysisTrial 1Trial 2Trial 3mass of silver produced by the reaction(g)(Mass of Beaker and silver)-(Mass of empty Beaker)=moles of solid copper used in reaction(mol Cu)g Cu x mol/63.55g=moles of solid silver produced in reaction(mol Ag).340.679.00152.00315g Ag x mol/107.84g=Determine the mole ratio.2.07mol Ag)/mol Cu)=Average Mole Ratio/ round to whole number!!

Answered: Image /qna-images/answer/ba61b7c2-0e33-4f48-9679-95b434d94af2.jpg

LAB 06 Mole to Mole Relationship between Cu and Ag Lab-procedures-notes-Help Lab Results Record and calculate the following: Mass of the empty beaker(g) Mass of Copper Added to Beaker(g) Mass of Silver and Beaker(g) Trial 1 Trial 2 Trial 3 110.00 110.000 0.100 0.200 110.340 110.679 Note the color Before Clear solution/copper solid Note the color After Light Bleu Data Analysis Trial 1 Trial 2 Trial 3 mass of silver produced by the reaction(g) (Mass of Beaker and silver)-(Mass of empty Beaker)= moles of solid copper used in reaction(mol Cu) g Cu x mol/63.55g= moles of solid silver produced in reaction(mol Ag) .340 .679 .00152 .00315 g Ag x mol/107.84g= Determine the mole ratio. 2.07 mol Ag)/ mol Cu)= Average Mole Ratio/ round to whole number

LAB 06 Mole to Mole Relationship between Cu and Ag Lab-procedures-notes-Help Lab Results Record and calculate the following: Mass of the empty beaker(g) Mass of Copper Added to Beaker(g) Mass of Silver and Beaker(g) Trial 1 Trial 2 Trial 3 110.00 110.000 0.100 0.200 110.340 110.679 Note the color Before Clear solution/copper solid Note the color After Light Bleu Data Analysis Trial 1 Trial 2 Trial 3 mass of silver produced by the reaction(g) (Mass of Beaker and silver)-(Mass of empty Beaker)= moles of solid copper used in reaction(mol Cu) g Cu x mol/63.55g= moles of solid silver produced in reaction(mol Ag) .340 .679 .00152 .00315 g Ag x mol/107.84g= Determine the mole ratio. 2.07 mol Ag)/ mol Cu)= Average Mole Ratio/ round to whole number

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.74QE: Lead poisoning has been a hazard for centuries. Some scholars believe that the decline of the Roman...

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