Kim is waiting for the results of her physics exam. She walks 8.0 metres north in 5.0 seconds, then 25 metres south in 15.0 seconds, then 10.0 metres north in 10.0 seconds. Use this information to answer the following questions: (1) What is Kim's average speed? (ii) What is Kim's average velocity? A) Kim's speed is 1.4 m/s B) Kim's speed is 0.23 m/s C) Kim's speed is -0.23 m/s OD) Kim's speed is -1.4 m/s OE) Kim's velocity is 1.4 m/s [N] F) Kim's velocity is 0.23 m/s [S] G) Kim's velocity is 0.23 m/s [N] OH) Kim's velocity is 1.4 m/s [S] Clear selection

University Physics Volume 1
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Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter3: Motion Along A Straight Line
Section: Chapter Questions
Problem 26P: The Shanghai maglev train connects Longyang Road to Pudong International Airport, a distance of 30...
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QuesuvI Z VETJ
Points: 2
Kim is waiting for the results of her physics exam. She walks 8.0 metres north in 5.0 seconds,
then 25 metres south in 15.0 seconds, then 10.0 metres north in 10.0 seconds. Use this
information to answer the following questions:
(1) What is Kim's average speed?
(ii) What is Kim's average velocity?
DA) Kim's speed is 1.4 m/s
B) Kim's speed is 0.23 m/s
C) Kim's speed is -0.23 m/s
D) Kim's speed is -1.4 m/s
E) Kim's velocity is 1.4 m/s [N]
F) Kim's velocity is 0.23 m/s [S]
G) Kim's velocity is 0.23 m/s [N]
ⒸH) Kim's velocity is 1 4 m/s [S]
Clear selection
Question 3 of 13
Transcribed Image Text:QuesuvI Z VETJ Points: 2 Kim is waiting for the results of her physics exam. She walks 8.0 metres north in 5.0 seconds, then 25 metres south in 15.0 seconds, then 10.0 metres north in 10.0 seconds. Use this information to answer the following questions: (1) What is Kim's average speed? (ii) What is Kim's average velocity? DA) Kim's speed is 1.4 m/s B) Kim's speed is 0.23 m/s C) Kim's speed is -0.23 m/s D) Kim's speed is -1.4 m/s E) Kim's velocity is 1.4 m/s [N] F) Kim's velocity is 0.23 m/s [S] G) Kim's velocity is 0.23 m/s [N] ⒸH) Kim's velocity is 1 4 m/s [S] Clear selection Question 3 of 13
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