Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg -f Evaluating, we get: f = mg But the frictional force is expressed as the product of coefficient and the normal force so. Hs = mg For an inclined plane. The normal force is n=mg Then, Hs=mg cos(e) so: Hs= tan(0)

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 76PQ: Jamal and Dayo are lifting a large chest, weighing 207 lb, by using the two rope handles attached to...
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A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction μs by measuring the critical angle θ where slipping occurs.

 

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Just before slipping, we say that the block is still at rest, so the net force on the x-axis is:
EFx=mg
-f
Evaluating, we get:
f
= mg
But the frictional force is expressed as the product of coefficient and the normal force so.
Hs
= mg
For an inclined plane. The normal force is
n=mg
Then,
Hs=mg
cos(e)
so:
Hs=
tan(0)
Transcribed Image Text:Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg -f Evaluating, we get: f = mg But the frictional force is expressed as the product of coefficient and the normal force so. Hs = mg For an inclined plane. The normal force is n=mg Then, Hs=mg cos(e) so: Hs= tan(0)
to
Transcribed Image Text:to
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