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- Consider the following function: public void bSearch(int[] A, int value, int start, int end) { if (end value) { return bSearch(A, value, start, mid); } else if (value > A[mid]) { return bSearch(A, value, mid+1, end); } else { return mid; } } The mutation program P' changes the part as shown below. } else if (value > A[mid]) { return bSearch(A, value, mid+2, end); } else { return mid; } A test input is given t1: {A = [2, 3, 5, 7, 10, 11], value = 6, start=0, end=5}. Which statement below best describes the mutant with regards to the test input? O a. t1 resolves mutant P O b. The mutant P' with regards to test input t1 is live.Run the programme and identify the outputs: void Test (int z[]) #include using namespace std; void Test (int []); int main () { int myArr [4]={3,4,5,6}; { int temp=z[3] ; z[3]=z[0]; z [0]=temp; for (int i=0;i<4;i++) cout<int LED void setup () { pinMode (LED,OUTPUT) ; void loop 0 digitalWrite (LED,HIGH); delay (1000) ; digitalWrite (LED, LOW) ; delay (1000); For the following circuit board, the following code was applied to make the LED blink every one second. 1- If the LED was connected to pin 5 and the delay was 3 seconds. Modify the code to accommodate these changes. 2- How does the LED blinking changes between the two codes? DIGITAL (PWM 0O UNO ARDUINO ANALOG 222222void deleteRange( int from, int to) { int i, j = 0; for (i = 0; i < counter; i++) { if (i <= from - 1 || i >= to + 1) { A[j] = A[i]; j++; } } for (int i = 0; i < j; i++) cout << A[i] << " "; } Above method deletes range of elements from an array. Please explain the logic of above code in simple english (algorithm and comments).inhinclude Rsing namespace std; int maxResult( ) int maxVal for (int i { for (int j = 0; j <= n 0; i <= n; i += a) i; j += b) %3D %3D float z = (float)(n (i + j)) / (float)(c); if (floor(z) { int x = int y ceil(z)) i / a; j/ b; maxVal = max(maxVal, x + y (int)z); return maxVal; } int main() { max cout << maxResult( ); return 0; 1 } Input Compilation failed due to fellowing ons main.cpp:7:23: error: 'n' was not declared in this scope 7| for (int i = 0; i <= n; i a) main.cpp:7:31: error: 'a was not declared in this scope for (int i = 0; i <= n; i t= a) %3D main.cpp:9:36: error: b' was not declared in this scope | 6 for (int j = 0; j <= n - i; j - b) %3D main.cpp:11:45: error: 'c was not declared in this scopeExplain the function of the given code: int timer = 100; int ledPins[] = { 2, 7, 4, 6, 5, 3 }; int pinCount = 6; void setup() { for (int thisPin = 0; thisPin = thisPin--) { digitalWrite(ledPins[thisPin], HIGH); delay(timer); digitalWrite(ledPins[thisPin], LOW); } 0;void deleteRange( int from, int to) {int i, j = 0;for (i = 0; i < counter; i++) {if (i <= from - 1 || i >= to + 1) {A[j] = A[i];j++;}}for (int i = 0; i < j; i++)cout << A[i] << " ";} Above method deletes range of elements from an array. Consider array A[] globally declared and counter is its size. Please explain the logic of above code in simple english (algorithm and comments).int main() ( int counter, first, last, next; first = 1; last = 2; for (counter = first; counter <= last; counter++) cout << "\n next counter * counter; cout <« " ww " « counter; " « next; counter = first; while (counter <= last)( cout <« "\n " « counter; next = counter * counter; cout <« " " « next; counter++; counter = first; do ( cout <« "\n " « counter; next = counter * counter; cout << " " « next; ww counter++; } while (counter < last); }using System; class HelloWorld { static void Main() { int rows=21; int columns=76; for(int i=0;i<rows;i++) //for loop for printing the pattern for 21 rows { for(int j=1;j<=columns;j++) //for loop for printing the pattern in 76 columns { if((i+j)%7!=1 ) //if the addition of i and j does not give remainder of 1 when divided by 7 then Console.Write("-"); //print dash - on console else //otherwise peint a space on console Console.Write(" "); } Console.WriteLine(); //print a newline for printing on new row... } } }using namespace std; int main() int i, m=0,n=4; float arr[100] (55,66,88,1); for(i=0; iOutputs of the following: void main () { int M[3]; int "ptr; ptr=M; *ptr=100; ptr++; "ptr=200; ptr=&M[2]; *ptr=300; for (int n=0; n<3; n++) cout <2. code locations Consider the following C code and the corresponding assembly code: void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; C = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: (continued on next page)SEE MORE QUESTIONSRecommended textbooks for youC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr