In the maximum key deletion operation on heaps, the first step is a delete the first element b exchange the first and last element c reverse the heap elements d delete the last element
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In the maximum key deletion operation on heaps, the first step is
a |
delete the first element |
|
b |
exchange the first and last element |
|
c |
reverse the heap elements |
|
d |
delete the last element |
Step by step
Solved in 3 steps
- Design a data type that supports the following operations: insert, delete the maximum, and delete the minimum (all in logarithmic time); andfind the maximum and find the minimum (both in constant time). Hint: Use two heapsProgramming language: JAVA Show the heap-based(min) priority queue constructed by inserting the following elements, either graphically or by listing the contents of the underlying array 8 6 0 4 2 1 3 5 7 9Starting with an empty priority queue, represented as heap, draw the heap that results from: enqueue 14 enqueue 16 enqueue 18 enqueue 10 enqueue 19 enqueue 40 dequeue 5 17 +
- List-Based Heap Implementations: The book starts out by discussing the concept of a priority queue and how to implement it conceptually. Then, the first implementation is presented: using an array or Python sequence to represent the heap. Data Storage: The book stores elements of a priority queue within a custom object (an _Item) which wraps and provides almost no support for the stored data. For this section, you will be storing your key and value as an ordered pair (or tuple) of two values where the first element is the key and the second element is the value. 1. What are the inherent benefits and drawbacks of this (array-based) backing representation? Discuss with respect to implementation, efficiency, and memory usage. (PI 1.2/ABET[1], PI 6.1/ABET[6])void insert(int p); // Insert adds the element p to the heap. // // In this heap the element is an int and IS the priority. // // We do not know at this abstract level if this will be // a min-heap or a max-heap (or even something else like // a fibonacci heap) and those details will be added in // the class that implements this heap interface. // Duplicate values are allowed. // // Error: The insert should fail if the heap is "full" // meaning the array is maxed out and there is no room // in the array for another element. In this case // simply return, and do nothing. //Min-heap example: // Suppose we have the following min-heap: // 3, 5, 4, 12, 6, 9 // After inserting 2, the min-heap now looks as follows: // 2, 5, 3, 12, 6, 9, 4 Your task is to implement the methods below in MinHeap.java for a min-heap using the instructions in Heap.java. You should not modify the code in Heap.java. Hint:…class Solution: def minCostConnectPoints(self, points: List[List[int]]) -> int: # start a visited set and min heap vis = set() min_heap = [(0,points[0])] res = 0 while min_heap: for _ in range(len(min_heap)): # check if point at top of heap is not already visited while tuple(min_heap[0][1]) in vis: heapq.heappop(min_heap) dist, point = heapq.heappop(min_heap) # add distance to the result and add that point to the visited set res += dist vis.add(tuple(point)) # we'll stop when the len of visited set becomes equal to length of all points if len(vis) == len(points): return res for i in range(len(points)): if points[i] == point or tuple(points[i]) in vis:…
- There is an algorithm for making the heap complete:1. Remove the node at the root.2. Move the node in the last position to the root.3. Trickle the last node down until it is below.When this algorithm is applied continually, the data is removed from the heap in sorted order. Write the code for the Remove and TrickleDown methods in c#.Sort the stack values either ascending or descending without using stack builtin classes for eg Stack before sorting : 5 | -2 | 9 | -7 | 3 where 3 is the top elementStack after sorting : -7 | -2 | 3 | 5 | 9 where 9 is the top elementAdd the following operation to the Class StackClass: void reverseStack(StackClass<T> otherStack); This operation copies the elements of a stack in reverse order onto another stack. Consider the following statements: StackClass<T> stack1; StackClass<T> stack2; The statement stack1.reverseStack(stack2); copies the elements of stack1 onto stack2 in the reverse order. That is, the top element of stack1 is the bottom element of stack2, and so on. The old contents of stack2 are destroyed and stack1 is unchanged. Write the definition of the method to implement the operation reverseStack. Also write a program to test the method reverseStack. In StackClass.java, please finish method - public void reverseStack(StackClass<T> otherStack) and testing main program – Problem53.java. Note: java programming, please use given outline code public class Problem53{ publicstaticvoidmain(String[] args){ StackClass<Integer> intStack = newStackClass<Integer>();…
- Add the following operation to the Class StackClass: void reverseStack(StackClass<T> otherStack); This operation copies the elements of a stack in reverse order onto another stack. Consider the following statements: StackClass<T> stack1; StackClass<T> stack2; The statement stack1.reverseStack(stack2); copies the elements of stack1 onto stack2 in the reverse order. That is, the top element of stack1 is the bottom element of stack2, and so on. The old contents of stack2 are destroyed and stack1 is unchanged. Write the definition of the method to implement the operation reverseStack. Also write a program to test the method reverseStack. In StackClass.java, please finish method - public void reverseStack(StackClass<T> otherStack) and testing main program public class Problem53{public static void main(String[] args){StackClass<Integer> intStack = new StackClass<Integer>();StackClass<Integer> tempStack = new StackClass<Integer>(); //Please…Consider the Stack ADT: Stack: push(x) adds x to top of stack pop() removes top element of stack and returns it size() returns number of elements in stack Select all options that allow for an efficient implementation based on the discussions from class. For any array implementation, you can assume the array is large enough so that making a larger one is not needed when pushing an item to the stack. Using an array with the top at the front of the array. Using an array with the top at the back of the array. Using a singly linked list with the top at the head of the list. Using a singly linked list with the top at the tail of the list. ENGA SpecialStackTM is a stack modified to support the following two operations: PUSHCLEAR(v) successively pops consecutive items from the top of the stack that are less than u, then pushes v onto the stack. POP() deletes the item at the top of the stack. Assume these operations are implemented using a singly-linked list. PUSHCLEAR(v) iter- ates through the linked list to pop the applicable items and then adds v to the beginning. POP() deletes the first item. (a) Describe the ordering of values on the stack. (b) Explain how a single call to PUSHCLEAR(V) could take (n) time. (c) If we assume that every operation takes linear time, we get a naive bound of O(n²) on the total runtime. But this doesn't consider the fact that these expensive operations happen infrequently so let's analyze it more closely. Show that any sequence of n operations takes O(n) time. -