In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al₂O₂) dissolved in molten cryolite (Na, AIF,), resulting in the reduction of the Al₂O, to pure aluminum. Suppose a current of 8900. A is passed through a Hall-Heroult cell for 78.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. 0 H 0.0 8 X dh

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al₂O₂) dissolved in molten cryolite (Na, AIF,), resulting in the reduction of the Al₂O, to pure aluminum. Suppose a current of 8900. A is passed through a Hall-Heroult cell for 78.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. 0 H 0.0 8 X dh

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 80AP

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