In the figure a thin glass rod forms a semicircle of radius r = 4.30 cm. Charge is uniformly distributed along the rod, with +q = 1.59 pC in the upper half and -q = -1.59 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? +q P -X

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter25: Gauss’s Law
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Problem 43PQ: The nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R),...
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In the figure a thin glass rod forms a semicircle of radius r = 4.30 cm. Charge
is uniformly distributed along the rod, with +q = 1.59 pC in the upper half
and -q = -1.59 pC in the lower half. What is the magnitude of the electric
field at P, the center of the semicircle?
+q
A
-9
x
Transcribed Image Text:In the figure a thin glass rod forms a semicircle of radius r = 4.30 cm. Charge is uniformly distributed along the rod, with +q = 1.59 pC in the upper half and -q = -1.59 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? +q A -9 x
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