In the circuit shown below, let V = (70Z - 40°) V, and find: (a) I1 (b) I₂ (c) 13 Enter angles between -180° and 180°. I₁ Vs +1 -j5Q 50 (a) I₁ = кора (b) I2 = A (C) I3 = = 0 40° A www I₂ 13 j5Q
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- QUESTION 3 An inductor, a capacitor, and a resistor are connected in series with a function generator. The inductor drops 5V RMS, the capacitor drops 20V RMS, and the resistor drops 2V RMS. Find the magnitude of the total voltage. O 27V RMS O 15V RMS O 38V RMS O 9V RMSQUESTION 3 An inductor, a capacitor, and a resistor are connected in parallel with a function generator. The inductor draws 100mA RMS, the capacitor draws 150mA RMS, and the resistor draws 200mA RMS. Find the magnitude of the total current. O 450mA RMS O 544mA RMS O 352mA RMS O 206mA RMSDraw a seven-segment display, show the number highlighted in figure 1 (d3 -d0 are the input, a -g are the outputs). III. Simulation Wavetorm Editor - Cers/Ahmad Fainuz/Desanop/DLD Lab Practice/bedseg - beaeg - bcaseg 2018o03121936sim.vwwt Ee ep Ea w smutation search altera.com Haster Time Bar: ops Pointer: s29 us Start End iterval 529 us o ps 0 ps २ 2.56 us S12 us 75 us 10.24 us 12 s 15.36 us 172 us value at Name Ops do Figure 1
- QUESTION 5 A resistor, a capacitor, an inductor, and a mystery component are connected in parallel. The resistor has a resistance of 300N, the capacitor has a reactance of 2500, and the inductor has a reactance of 6000. The total impedance of the circuit is 59.52-j119.640. What is the mystery component? O there is no mystery component O resistor O inductor O capacitorShown in the figure below is an "RC" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 11.58 Volts and is running at a frequency of f = 1.326e+04 Hz. resistor has a resistance of R = 3750 2 and the capacitor has an capacitance of C = 3.17e-09 Farads. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit tot = Determine the numerical value of Ztot = Determine the numerical value of Pztot= Determine the current through the circuit: • I(PEAK) = • I(RMS) = Determine the voltage across the resistor: Amps Amps S2 C degreesShown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…
- can you please give me the comple solution for this question, thanks. A certain voltage function contains a constant term, a fundamental and third harmonic. The maximum value of the fundamental is 85 % of the constant term and the maximum value of the third harmonic is 55 % of the constant term. If the effective value of this function is 180.3V, find the magnitude of the two harmonics. A.IstHarmonic = 75 V , 3rd Harmonic = 120V B. Ist Harmonic = 80 V , 3rd Harmonic = 125V C. IstHarmonic = 120 , 3rd Harmonic = 75V D. Ist Harmonic = 125 V , 3rd Harmonic = 80V E. NOTAQUESTION 5 A resistor, a capacitor, and an inductor are connected in series with a function generator. The resistor has a resistance of 2kO, the inductor has a reactance of 5000, and the capacitor has a reactance of 1kQ. The circuit has a total current of 100mA RMS. Find the total voltage. O 155-j720 V O 305+j80 V 120+j30 V 200-j50 VP 269 W, Q = 150 VAR (capacitive). The power in the complex form is: %3D Select one: a. 150 + j269 VÀ b. None of these c. 150- j269 VA d. 269-j150 VÀ
- 4. A capacitor now is connected in parallel with R1 to reduce the ripple. Find the value of the capacitance needed to make the following ripple index less than 5% through PSpice simulation study. V -×100% -V o,min 0,max rpp RFP = -x100% = V dc dc D1 Dbreak R1 V1 1k VAMPL = 169.71 FREQ = 50 VoQUESTION 4 A resistor, a capacitor, and an inductor are connected in series with a function generator. The resistor has a resistance of 1.5k2, the inductor has a reactance of 1.2kQ, and the capacitor has a reactance of 2002. The circuit has a total current of 172mA RMS. Find the total voltage. O 310V233.7 O 74.5VL-14° 188V273.2 O 44.4VL-25.3°For the circuit diagram in figure Q22: which of the following is the total impedance? 12 Ri 10R R2||5R Figure Q22 V 220V40 50HZ L1 315mH C1=350uF O a. 3.33/0° O b. 4.71290°2 O c. 7.3304-19.66° O d. 10.37261.19°2