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In the circuit in Fig. 3-16(a) the switch is in the closed position for a long time before it is opened at i = 0. Find the inductor current i(t) for t> 0. When the switch is in the closed position for a long time, the capacitor voltage is charged to 10 V and there is no current flowing in the capacitor. The inductor behaves as a short circuit, and the inductor current is = 2 A. Thus, when the switch is open, we have i(0~)= 2 and v.(0-)= 10; the input voltage is 10 V, and therefore it can be represented as 10u(t). Next, using Fig. 3-10, we construct the transform circuit as shown in Fig. 3-16(b). i(1) SN 10 V ww wwofa

In the circuit in Fig. 3-16(a) the switch is in the closed position for a long time before it is opened at i = 0. Find the inductor current i(t) for t> 0. When the switch is in the closed position for a long time, the capacitor voltage is charged to 10 V and there is no current flowing in the capacitor. The inductor behaves as a short circuit, and the inductor current is = 2 A. Thus, when the switch is open, we have i(0~)= 2 and v.(0-)= 10; the input voltage is 10 V, and therefore it can be represented as 10u(t). Next, using Fig. 3-10, we construct the transform circuit as shown in Fig. 3-16(b). i(1) SN 10 V ww wwofa

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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In the circuit in Fig. 3-16(a) the switch is in the closed position for a long time before it is opened at i = 0. Find the inductor current i(t) for t> 0. When the switch is in the closed position for a long time, the capacitor voltage is charged to 10 V and there is no current flowing in the capacitor. The inductor behaves as a short circuit, and the inductor current is = 2 A. Thus, when the switch is open, we have i(0-) = 2 and v,(0-) = 10; the input voltage is 10 V, and therefore it can be represented as 10u(t). Next, using Fig. 3-10, we construct the transform circuit as shown in Fig. 3-16(b). i(1) ell 5N 10 V wwofo
Transcribed Image Text:In the circuit in Fig. 3-16(a) the switch is in the closed position for a long time before it is opened at i = 0. Find the inductor current i(t) for t> 0. When the switch is in the closed position for a long time, the capacitor voltage is charged to 10 V and there is no current flowing in the capacitor. The inductor behaves as a short circuit, and the inductor current is = 2 A. Thus, when the switch is open, we have i(0-) = 2 and v,(0-) = 10; the input voltage is 10 V, and therefore it can be represented as 10u(t). Next, using Fig. 3-10, we construct the transform circuit as shown in Fig. 3-16(b). i(1) ell 5N 10 V wwofo
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