In part a, total mass equals mass (mass of bike + mass of So0-Hoo + mass of Eun Yeong-Ro) is to be considered as he needs to apply force such that he needs to move his mass, mass of bike and mass of Eun Yeong-Ro. In the question it is given that he travels a vertical distance of 6.39m. This will be the distance traveled. Using formula of work done= Force*Displacement we calculate the work done. From the Work-Energy theorem, work done is equal to the change in kinetic energy. Initially, he was moving with a velocity of 6m/s but later reduced to 1.43m/s. Here, initial velocity is taken as 6m/s and final velocity as 1.43m/s Power can be written as the rate of change of work done. P=Work/Time. From part a and part b we can calculate the total work done. The question is given to calculate the power for 30 minutes. Converting it to seconds by multiplying by 60.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.19P: Plot the earths gravitational acceleration g(m/s2) against the height h (km) above the surface of...
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Pls explain in DETAIL how did you come up with the solution. I need to present it in class and I didn't know how
3.
In part a, total mass equals mass = (mass of bike + mass of Soo-Hoo + mass of Eun Yeong-Ro) is to be considered as
he needs to apply force such that he needs to move his mass, mass of bike and mass of Eun Yeong-Ro.
In the question it is given that he travels a vertical distance of 6.39m. This will be the distance traveled.
Using formula of work done= Force*Displacement we calculate the work done.
From the Work-Energy theorem, work done is equal to the change in kinetic energy. Initially, he was moving with a
velocity of 6m/s but later reduced to 1.43m/s. Here, initial velocity is taken as 6m/s and final velocity as 1.43m/s
Power can be written as the rate of change of work done.
P=Work/Time.
From part a and part b we can calculate the total work done. The question is given to calculate the power for 30
minutes. Converting it to seconds by multiplying by 60.
Transcribed Image Text:3. In part a, total mass equals mass = (mass of bike + mass of Soo-Hoo + mass of Eun Yeong-Ro) is to be considered as he needs to apply force such that he needs to move his mass, mass of bike and mass of Eun Yeong-Ro. In the question it is given that he travels a vertical distance of 6.39m. This will be the distance traveled. Using formula of work done= Force*Displacement we calculate the work done. From the Work-Energy theorem, work done is equal to the change in kinetic energy. Initially, he was moving with a velocity of 6m/s but later reduced to 1.43m/s. Here, initial velocity is taken as 6m/s and final velocity as 1.43m/s Power can be written as the rate of change of work done. P=Work/Time. From part a and part b we can calculate the total work done. The question is given to calculate the power for 30 minutes. Converting it to seconds by multiplying by 60.
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