Please provide me complete and correct solution of all the parts of question thanks 3 | In each of the following cases, give a O estimate for the number of times the* L-statement r:= r +1 is executed. Justify each answer. You're free to make assumptionsabout the input size n.a) for i = 1 to nfor j = 1 to ifor k = 1 to jb) i:=nwhile i >1I:= r +1i:= i/2c) j:= nwhile j 21for i = 1 to nr:= r+1I:= x +1j:= j/2

For answering this question, I am assuming that n=3 and x=0(initial) are here for all the programs.…

In each of the following cases, give a e estimate for the number of times the statement z:= 1+ 1 is executed. Justify each answer. You're free to make assumptions about the input size n. a) for i =1 to n for j =1 to i for k =1 to j b) i := n while i21 c) j:= n while j 21 for i =1 to n 1:-I+1 1:=I+1 i:- i/2 1:=1+1 j:= j/2

In each of the following cases, give a e estimate for the number of times the statement z:= 1+ 1 is executed. Justify each answer. You're free to make assumptions about the input size n. a) for i =1 to n for j =1 to i for k =1 to j b) i := n while i21 c) j:= n while j 21 for i =1 to n 1:-I+1 1:=I+1 i:- i/2 1:=1+1 j:= j/2

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Problem Statement: Consider a permutation of numbers from 1 to N written on a paper. Let's denote the product of its element as 'prod' and the sum of its elements as 'sum'. Given a positive integer N, your task is to determine whether 'prod' is divisible by 'sum' or not. Input Format: First input will be an integer T. It depicts a number of test cases. Followed by the value for each test case. Each test case will contain an integer N (1<= N <=10^9). It is nothing but the length of the permutation. Output Format: For each test case, print "YEAH" if 'prod' is divisible by 'sum', otherwise print "NAH".
Exercise III: Catalan numbers For n e N, denote by c, to be the number of ways to form a "mountain range" with n upstrokes (U) and n downstrokes (D) that all stay above a horizontal line. For instance: for n = 1, only UD is allowed, so c = 1; • for n = 2, only UUDD and UDUD are allowed, so c2 = 2. 1. Check that c3 = 5 by writing down or drawing all possible options. 2. Consider the power series +00 g(x) = 2 n=0 (by definition co = 1) called the generating function of the sequence (en). Justify that cn < 4" for each n, and deduce that the radius of convergence of g is at least 1/4. 3. It can be show that for r E (-1/4, 1/4), g(x) = 1+ xg(r)? and therefore 1- VI 4.x g(x) = 2.x Use this formula and the known power series of V1+ x to write the first terms of the power series expansion of g, in the form g(x) = co + c1x + c2x2 + C3x + c4x* + ·.. Show how you obtain a few terms, but you do not need to show all computations and you can use a calculator for fractions. Check that you recover co,…
user_num1 and user_num2 are read from input. If user_num1 is less than 0, output 'user_num1 is negative'. If user_num2 is greater than 8, assign user_num2 with 5. Otherwise, output 'user_num2 is less than or equal to 8'. Click here for examples ● 1 user_num1 = int(input()) int(input()) 2 user_num2 = 3 | 4 user_num int (input) 5 user_num2 int (input 0) 6 if user_num1 8: 9 user_num2 = user_num2-5 10 else: 11 print (user_num2 is less than or equal to 8') 12 print('user_num2 is', user_num2)
]: Write a piece of code that calculates the uncertainty SP from the error propagation rule for sums, SP = 2√√√(SL)² + (SW)² A few hints: Again, you're translating the above equation into code. • Your result should be stored in a variable uncertainty_P_errorprop • For the square root function, use np. sqrt() • For squares, use ** #YOUR CODE HERE raise Not ImplementedError() ]: ▼ # Print the uncertainty print ("uncertainty of circumference P from error propagation: 11 , uncertainty_P_errorprop)
varinouputs.m x TEST.m x+ function a = varinouputs (varargin) Bfor n=1:nargin if sum (size (varargin(n})> s=s+varargin{n): - 2 sa varargin(n) > 3 end end as disp(Inargin nargout]):| Q1: Answer all of the following (1-10). 1- We can use neip and 00C commands/functions to get information on how to use a function in MATLAB. 2- MATLAB variable names must start with a letter 3- An example of a built-in variable in MATLAB is pi or i 4- The result of the following command A=2*(3+2)/3^-1 in MATLAB is: A 30 5- If B-5+6i, then B' and transpose(B) commands are the same. True or False? Faise 6- Let a=[2, 4, 6] and b=[5; 2; 6]. Which of the following operations would not give an error? a) a+b; b, d, e and f b) a'-b; c) a.*b; d) b*a; e) a./b'; f) a.^a; 7- If C-[1, 5, 6, 10, 3, 8], then C(1)=, 8- If D-[1, 2, 3; 4, 5, 6; 7, 8, 9], then sub2ind([3 3], [3 2], [2 2])= 5 6 D(2,3)=. D(end-2)=_3 9- The result of the following command E=0.1 b) evennumber-numel(A(mod(A,2)so)); Q3: Define a 2-D array (matrix)…
3- If a = [123; 4 5 6; 7 8 9]; and b= ([1,2,2,3],:). The value of b= ? O error using of matlab expression O [1 2 3 4 5 6;4 5 6;7 8 9] O [1223;1 2 2 3;1 2 2 3] O [1 4 7,2 5 8;2 5 8;3 6 9]
6. What is the difference between if (p { }? == q) {...} and if (*p == *q)
Modify program P34_1.cpp to compute the side area, of a cylinder and the area and volume of a sphere, depending on the choice that the user makes. total area, and volume Your program should ask users to enter 1 to choose cylinder or 2 for sphere, and display an "invalid choice error" for other values. For a cylinder, we want to compute: Side area: (2*PI*r) h Total Area: 2*(PI*r2) + Side area Volume: (PI*r2)*h For a sphere, we want to compute: Surface area: 4 *PI*r2 Volume: (4.0/3.0)*PI*r3. Use overloading whenever possible.
30The following code is supposed to return n!, for positive n. int factorial(int n){ if (n == 0) return 1; else return (n + factorial(n - 1));} An analysis of the code using our "Three Question" approach reveals that: Group of answer choices it fails the base-case question. it fails the smaller-caller question. it fails the general-case question. it passes on all three questions and is a valid algorithm. None of these is correct.
le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"
2.a Σ : {c,A,G,T}, L = { w : w = CAG™T™C, m = j + n }. For example, CAGTTC E L; CTAGTC ¢ L because the symbols are not in the order specified by the characteristic function; CAGTT ¢ L because it does not end with c; and CAGGTTC € L because the number of T's do not equal the number of A's plus the number of G's. Prove that L¢ RLs using the RL pumping theorem.
Complete the function ratio_similarity, which computes the ratio of "similarity" between two non-empty strings. The ratio is computed as follows: 2 (the number of matches of characters) / (total number of characters in both strings) The matches are determined in pairwise fashion. For example, consider the strings abcdef and abdce. The three characters at indexes 0, 1 and 4 match. Therefore, the similarity ratio is 2 * 3/(6 + 5) = 0.5454 .... Examples: Function Call string_similarity('abcdef', 'abdce') string_similarity('dragon', 'flagon') string_similarity('stony', 'stony') string_similarity('Stony Brook University', 'WolfieNet Secure') string_similarity('yabba dabba doo', 'bippity boppity boo') string_similarity('Wolfie the Seawolf', "What's...a Seawolf?") [ ] Return Value 3 4 5 # Test cases 6 print (string_similarity('abcdef', 'abdce')) 7 print (string_similarity('dragon' 1 'flagon')) 'stony')) 0.5454545454545454 0.6666666666666666 1.0 0.0 0.058823529411764705 0.4864864864864865 1…