In cats, the black (B) gene has three alleles that control the density of eumelanin granules in the hair shaft. The B allele is dominant and produces a black coat. The b allele reduces black to a dark brown, chocolate color in bb homozygotes. The b' allele further reduces melanin density to produce a medium-brown coat in homozygotes called cinnamon in homozygotes. b is dominant to b' so the dominance hierarchy is B > b > b'. A mating between black and chocolate cats yields kittens of all 3 coat colors (black, chocolate and cinnamon). Use the dropdown menus to indicate parental genotypes: The genotype of the black parent was [Select] genotype of the chocolate parent was [Select] and the

In cats, the black (B) gene has three alleles that control the density of eumelanin granules in the hair shaft. The B allele is dominant and produces a black coat. The b allele reduces black to a dark brown, chocolate color in bb homozygotes. The b' allele further reduces melanin density to produce a medium-brown coat in homozygotes called cinnamon in homozygotes. b is dominant to b' so the dominance hierarchy is B > b > b'. A mating between black and chocolate cats yields kittens of all 3 coat colors (black, chocolate and cinnamon). Use the dropdown menus to indicate parental genotypes: The genotype of the black parent was [Select] genotype of the chocolate parent was [Select] and the

Name: 3 In cats, the black (B) gene has three alleles that control the densi
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Description: 3 In cats, the black (B) gene has three alleles that control the density of eumelaningranules in the hair shaft. The B allele is dominant and produces a black coat.The b allele reduces black to a dark brown, chocolate color in bb homozygotes.The b' a

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 1QP: The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show...

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In rabbits fur colour can be either gray black or blotchy. Blotchy is present as grey and black spots present in no specific pattern males are almost always are the grey or black while females can be gray, black or blotchy. However, a male individual is found that shows the blotchy pattern, and you, expect a nondisjunction event might to be to blame. Explain the inheritance of coat colour in rabbits and also provide an explanation for the blotchy male.
At least two pairs of genes control eye color. Both pairs influence the production of the pigment, melanin, but act independently. One pair of alleles is B (Brown color; dominant) and b (blue color); the other pair is A (pigment production; dominant) and a (no pigment production; albino). The gene pair aais epistatic to (masks) B and b and produces the nonpigmented eyes of the albino. What is the typeof gene interaction that exists between the two gene pairs? Give the genotypes and phenotypes of the possible offspring of the mating bbAa x Bbaa andi ndicate the parental phenotypes. (any method)
The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show linkage. What does that mean in terms of their relative locations in the genome? What does it mean in terms of how the two traits are inherited with respect to each other?
Ear Shape In pigs, erect-ears is dominant (E) to drooping-ears (e). 1) A farmer performs a test cross on his erect-eared sow (female pig). Explain the purpose of a test cross and describe the other individual involved in the cross. 2) Create a Punnett square for each test cross possibility. 3) Write a summary sentence explaining the result of each test cross.
Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous dominant for gene C, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I.Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers.What is the probability of one of the offspring of these two chickens having white feathers? (percentage)
Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous dominant for gene C, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I.Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers.In a population of 150 chickens, produced from the same parents, how many chickens would you expect to have pigmented feathers?
In otters fur colour can be either yellow or brown, and is determined by two alleles of the C gene. A heterozygous otter is observed to present a fur pattern of yellow and bear patches. Explain why this can occur.
Produce a Punnett square to illustrate the dihybrid cross described below: There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the dominant causative mutation. The mother is homozygous wild type at the same locus. Add a file here showing your diagram.
Two unlinked loci effect mouse hair color. AA or Aa mice are agouti. Mice with genotype aa are albino because all pigment production and deposition of pigment in hair is blocked. At the second locus, the B allele (black agouti coat) is dominant to the b allele (brown agouti coat). A mouse with an unknown genotype is mated with an albino mouse of genotype bbaa. Half of the offspring are albino, one quarter are black agouti, and one quarter are brown agouti. What is the genotype of the unknown parent?
In mice, the A allele causes agouti fur, the AY allele causes yellow fur and is dominant to the A allele. The homozygous AY AY genotype is lethal. Why is the AYAY homozygous condition lethal? The AY allele highly transcribes the merc gene which is lethal in a homozygous AYAY individual. None of the other answers are correct. The AY allele lacks an upstream merc gene which is required for normal embryonic development. The AY allele contains a null mutation in the A gene, which is required for normal embryonic development. The yellow pigment produced by A allele is required for survival.
In bears fur colour can be either yellow or tan, and is determined by two alleles of the C gene. A heterozygous bear is observed to present a fur pattern of yellow and tan patches. Explain why this can occur.
Two hedgehog parents are heterozygous at the spiny locus, each with genotype Ss. This locus affects the length of the individuals’ spines, which ranges from 1 cm in SS homozygotes to 3 cm in ss homozygotes.Inheritance of spine length in this family is entirely due to the spiny locus and it exhibits additivity. Remember that development of spines depends on thousands of genes, but we’re only considering this one gene because it’s the one that varies in a way that affects spine length in this family. a) List all of the phenotypes we could observe among offspring of these Ss heterozygote parents. b) What’s the probability that an offspring of these heterozygous parents is an SS homozygote? c) If the parents have exactly two offspring, what is the probability that the two hedgehog kids have no alleles in common? In other words, what’s the probability that one kid is SS and the other ss?