(b) Based on your sample, graph the 99% confidence interval for the population mean of all the distances the voters in Vanville County live from their nearest polling station. Enter the values for the lower and upper limits on the graph-to show your confidence interval. For the point (*), enter the claim 7.78 from the article. 0.000 99% confidence interval: 0.000 2.000 4.000 5.000 10.000 6.000 8.000 10.000 (c) Does the 99% confidence interval you constructed contradict the claim made in the article? Choose the best answer from the choices below. X O No, the confidence interval does not contradict the claim. The mean of 7.78 km from the article is inside the 99% confidence interval. O No, the confidence interval does not contradict the claim. The mean of 7.78 km from the article is outside the 99% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 7.78 km from the article is inside the 99% confidence interval. O Yes, the confidence interval contradicts the claim. The mean of 7.78 km from the article is outside the 99% confidence interval. 5 & In anticipation of an upcoming election, officials in Vanville County are looking at the distance from each voter's home to that voter's nearest polling station. Assume that the population of all such distances for voters in Vanville County is approximately normally distributed. An article for the newspaper Frontline Freedom claimed that the mean of this population is 7.78 km. You want to test this claim, so you select a random sample of 17 Vanville County voters, and for each you record the distance the voter lives from their nearest polling station. Follow the steps below to construct a 99% confidence interval for the population mean of all the distances voters in Vanville County live from their nearest polling station. Then state whether the confidence interval you construct contradicts the reporter's claim. (If necessary, consult a list of formulas.) (a) " Click on "Take Sample" to see the results for your random sample. Number of people 17 Sample standard Sample mean deviation 4.179 2.023 5 your 99% Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Take Sample Sample size: 1 Point estimate: Standard error: X Sample standard deviation: Critical values Margin of error: 0.005 = 2.921 Critical value: 0.010 = 2.583 99% confidence interval: 50.025 =2.120 Compute 0.050 = 1.746 40.100 = 1.337 8 B