In an experiment to determine the viscosity of some oil, a ball is dropped into the oil. The position of the ball is given by the formula y(t)=A+Bt+Ce^−Dt, where y is given in m, and t is the time in s. At t=0, y(0)=0.07 m, the y component of the velocity is zero and the y component of the acceleration is ay(0)=0.015 m/s^2. As t approaches infinity, the y component of the velocity approaches vy(∞)=0.55 m/s.
In an experiment to determine the viscosity of some oil, a ball is dropped into the oil. The position of the ball is given by the formula y(t)=A+Bt+Ce^−Dt, where y is given in m, and t is the time in s. At t=0, y(0)=0.07 m, the y component of the velocity is zero and the y component of the acceleration is ay(0)=0.015 m/s^2. As t approaches infinity, the y component of the velocity approaches vy(∞)=0.55 m/s.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 44P: Three displacement vectors of a croquet ball are shown in Figure P1.44, where |A|=20.0units,...
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In an experiment to determine the viscosity of some oil, a ball is dropped into the oil. The position of the ball is given by the formula y(t)=A+Bt+Ce^−Dt, where y is given in m, and t is the time in s. At t=0, y(0)=0.07 m, the y component of the velocity is zero and the y component of the acceleration is ay(0)=0.015 m/s^2. As t approaches infinity, the y component of the velocity approaches vy(∞)=0.55 m/s.
The problem asks you to find what A, B, C, and D are. I found that B = 0.55 m/s and I believe I can crack if I just knew what one more constant was. However, I am completely stumped.
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