In a population of 100 pea plants, there are two variations for flower color--purple and white. After counting the number of white plants were 9 plants. What percentage willl be purple plants (p^2+2pq)?
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In a population of 100 pea plants, there are two variations for flower color--purple and white. After counting the number of white plants were 9 plants.
What percentage willl be purple plants (p^2+2pq)?
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- In a population of 100 pea plants, there are two variations for flower color--purple and white. After counting, the nymber of white plants were 9 plants. What would be the number of plants that are heterozygous (2pq)?In a population of 100 pea plants, ther are two variations for flowers color-- purple and white. After counting, the number of white plants were 9 plants. What would be the nymber of plants that are heterozygous (2pq)?From a presumed testcross of 2 plants of genotype Aa x aa (in which A represents red and a represents white petals on a plant) we get 5000 red petal plants, and 5400 white petals plants. Using the Chi-squared test, what chi-squared value do we get for this?
- The narrow-sense heritability of the number of peas perpod in a population of sugar snap peas is 0.5. The meanof the population is 6.2 peas per pod. A plant breederselects one plant with 6.8 peas per pod and crosses witha second plant that has 8.0 peas per pod. What is the expected numbers of peas per pod among the offspring ofthis cross?There are two types of alleles: Type B1 and Type B2 (In total there are 10) Type B1 has 6 Type B2 has 4 Question: What is the probability of an individual in the offspring generation being homozygous [p^2] for B1? What is the probability of an individual in the offspring generation being homozygous [q^2] for B2? What is the probability of an individual in the offspring gen being heterozygous[2pq]?Complete the punnett square below for a cross between AA and aa A 21 a QUESTION 4 A Aa Complete the punnett square below for a cross between Aa and Aa. 03 Aa Aa
- If the tobacco plant parents are both heterozygous for color, what are the possible genotypes and phenotypes of their offspring? Complete the Punnett square below. What is the expected phenotypic ratio?The narrow-sense heritability (hN2) for potato weight in a starting population of potato plants is 0.42, and the mean weight is 1.4 pounds. If a breeder crossed plants with average potato weights of 1.9 and 2.1 pounds,respectively, what is the predicted average weight of potatoes fromthe offspring?Seed weight in a particular plant species is determined by pairs of alleles attwo loci (a+ a− and b+ b−) that are additive and equal in their effects. Plantswith genotype a− a− b− b− have seeds that average 1 g in weight, whereasplants with genotype a+ a+ b+ b+ have seeds that average 3.4 g in weight. Aplant with genotype a− a− b− b− is crossed with a plant of genotype a+ a+ b+b+.a. What is the predicted weight of seeds from the F1 progeny of this cross?b. If the F1 plants are intercrossed, what are the expected seed weights andproportions of the F2 plants?
- type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSwhy doesnt this chi square value fit the number of expected with independent assortment?What is the EXPECTED # of students who would be heterozygous (+/-) ? There were 15 students who examined their ALU PV92 genotype status. That semester we determined that there were 7 students who were -/- 4 students who were +/- 4 students who were +/+ Group of answer choices 2.4 4 5 7.2