Answered: If the position of a particle is…

Name: Subject: Dynamics of rigid bodiesshow your solution If the position of
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Subject: Dynamics of rigid bodiesshow your solution If the position of a particle is defined by[2 sin (7/5)t + 4] m, wheret is in seconds, constructthe s-t, v-t, and a-t graphs for 0

Science

Physics

If the position of a particle is defined by [2 sin (7/5)t + 4] m, wheret is in seconds, construct the s-t, v-t, and a-t graphs for 0

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 12CQ: Can the magnitude of a particle’s displacement be greater that the distance traveled?

See similar textbooks

Similar questions

The velocity of a particle as a function of time is given by v(t)=(3t-t )i-4 j all in S.I. units. a) What are the dimensions of the "-1 " in the – ti term? What are the units of the "3 " in the 3t i term? b) Find the position vector of the particle, r(t), if r(0) = -5 i- 2j :) Find the time ti > 0 when the position in the i direction is a maximum. d) Find a 1 -> 3 the average acceleration vector in the time interval 1 to 3 seconds.
A particle moves along the h-axis (dimension of length) so that: h = t3 - 3t2 - 45t (in feet, where "t" is in seconds) (a) Plot the h-t, v-t, and a-t graphs in 0 < t < 10 seconds.
(b) A military radar identified an unknown object flying above Andaman Sea. The Radar Intercept Officer (RIO) justified that this unknown flying object follows a motion equation, s(t) = sin t + 6t where s in meter and t in second. Justify whether 3-point central difference has higher accuracy in approximating the velocity of the unknown flying object at is backward difference. Use small increment, h = 10-3. second, comparing to 2-point forward difference and 2-point
The magnitude of a particle's velocity is observed to vary with time according to the equation: |v = Bt where Bis a positive constant. What are the units of B? т S m Om: s? O m· .3 m
A body moves in space , the location vector r = 2 2t i+tj +2 k m, How much the velocity of it at 2 second V = m/sec (aii 2 aic aïcrw za )?
If the position of a particle is defined by s = [2 sin (pi/5)t + 4] m, where t is in seconds, construct the s-t, v-t, and a-t graphs for 0 ... t ... 10 s.
Asap
A particle starts at the origin (x = 0) and moves in one dimension. The figure shows the velocity of the particle as a function of time. During whic range of times is the particle moving towards the origin? 8. 4 12 16 Time (s) Velocity (ms) 4.
Can the magnitude of a particle’s displacement be greater that the distance traveled?
After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of time is given by v=1.2i9.8tj where v is in meters per second and t is in seconds. The balls displacement away from the edge of the table, during the time interval of 0.380 s for which the ball is in flight, is given by r=00.3803vdt To perform the integral, you can use the calculus theorem [A+Bf(x)]dx=Adx+Bf(x)dx You can think of the units and unit vectors as constants, represented by A and B. Perform the integration to calculate the displacement of the ball from the edge of the table at 0.380 s.
In SI units, speeds are measured in meters per second (m/s). But, depending on where you live, you’re probably mole comfortable of thinking of speeds in terms of either kilometers per hour (km/h) or miles per hour (mi/h). In this problem, you will see that 1 m/s is roughly 4 km/h or 2 mi/h, which is handy to use when developing your physical Intuition. More precisely, show that (a) 1.0m/s=3.6km/h and 1.0m/s=2.2mi/h .
A car moves along a straight line, such that its speed over time is given by ds m = 2.t-10 dt S a) The function that describes the position s open parentheses t close parentheses of the particle as a function of time, if s open parentheses 0 close parentheses equals 10 (s in meters and t in seconds), is given by: b) The total distance traveled, in meters, by the particle from t equals 0 to t equals 9.5 seconds is: c) The net displacement or change in position (in meters) from t equals 0 to t equals 9.5 seconds is: d) The acceleration of the moving object when t equals7 seconds is: s(t)=t²-10-t+10 s(t)=t²-5.t+10 s(t) = 0.5-t²-10 t+10 s(t) = 0.5-t²-5-t+10 9 20.25 45.25 4.75 22.625 5.25 -4.75 -15 m s²