If, in addition to the constraints on glucose concentration listed previously, we have in the liver cell ATP concentration=3 mM and ADP concentration = 5 mM, what is the theoretical concentration of glucose-6-phosphate at equilibrium at pH = 7.4 and 37 °C? Express your answer to three significant figures and include the appropriate units. Theoretical concentration = O Value 3 d Units ?

If, in addition to the constraints on glucose concentration listed previously, we have in the liver cell ATP concentration=3 mM and ADP concentration = 5 mM, what is the theoretical concentration of glucose-6-phosphate at equilibrium at pH = 7.4 and 37 °C? Express your answer to three significant figures and include the appropriate units. Theoretical concentration = O Value 3 d Units ?

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter23: Organic Polymers, Natural And Synthetic

Section: Chapter Questions

Problem 46QAP: Glycolysis is the process by which glucose is metabolized to lactic acid according to the equation...

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Glycolysis is the process by which glucose is metabolized to lactic acid according to the equation C6H12O6(aq)2C3H6O3(aq) G=198 kJ at pH 7.0 and 25°C Glycolysis is the source of energy in human red blood cells. In these cells, the concentration of glucose is 5.0103 M, while that of lactic acid is 2.9103 M. Calculate AG for glycolysis in human blood cells under these conditions. Use the equation G=G+RT In Q, where Q is the concentration quotient, analogous to K.
For a given acid HA, it was determined that at pH 6.0 the concentration of the conjugate base [A] was 0.075 M and the acid [HA] was 0.025 M. What percent of this acid is ionized at pH 6.0? What is the pKa of this acid? What pH would this acid be 50% lonized?
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Assume that in a certain cell, the ratio of products/reactants or Keq = 614.9 (Keq is dimensionless) for the reaction Glucose + ATP <> Glucose-6-P + ADP, at a particular instant, the concentrations of each compound were Glucose =4.3M, ATP =10.5M, ADP =17.3M and G-6-P =23.5M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five significant figures.
Scenario A: 1 mole of glucose in the presence of unlimited oxygen is metabolized through aerobic respiration. Scenario B: 1 mole of glucose in the absence of oxygen is metabolized through anaerobic respiration. Would the number of moles of carbon dioxide produced in Scenario A be greater than, less than, or equal to the number of moles of carbon dioxide produced in Scenario B? Justify your answer.
Assume the standard Gibbs free energy change or deltaGO=5.02 kJ/mol for the reaction dihydroxyacetone phosphate glyceraldehyde-3-phosphate. Calculate the deltaG for this reaction at 13.6°C when DHAP =0.47M and G3P =0.0025M in kJ/mol to two decimal places. «< Question 25 of 28 A Moving to another question will save this response. Close Window
1. A. phosphoenolpyruvate (PEP) is one of the two phosphoryl group donors in the synthesis of ATP during glycolysis. In human erythrocytes, the steady state concentration of ATP is 2.24 mM, that of ADP is 0.25 mM, and that of pyruvate is 0.051 mM. Calculate the concentration of PEP at 25° C, assuming that the pyruvate kinase reaction (see figure 13-13) is at equilibrium in the cell. B. The physiological concentration of PEP in human erythrocytes is 0.023 mM. Compare this with the value obtained in A. Explain the significance of this difference.
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