If I have a Network-ID 127.91.220.100 of subnet , What is the broadcast address of this subnet? Kan you explain it
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If I have a Network-ID 127.91.220.100 of subnet , What is the broadcast address of this subnet? Kan you explain it
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- TCP sessions are full-duplex, which means that data can be sent in either direction during the lifetime of the session. Consider a session in which the connection is established, the client sends 100 data segments, all of them are ACKed, and all of the ACKS are received by the sender, then the session is ended by both sides closing the connect. How many segments in total have the SYN bit of the header set to 1? а. 209 O b. 2 6 с. d. 4 О е. 1Answer the following questions: The IP address is based on your student number SN as follow: The first byte is 198. The second byte is the 6th and 7th numbers of your SN, for example, if your SN is 438051221, the second byte is The third byte is the 8th and 9th numbers of your SN, for example, if your SN is 438051221, the third byte is The forth byte is 0. Consider a company which owns a license of this IP address. Write this IP address, for example 198.12.21.0 How many hosts at the maximum can be in this network? What are the first and the last addresses given to hosts? The company likes to divide its network into 10 subnets. Determine the necessary number of bits borrowed. Determine the new subnet mask. Determine the maximum number of hosts in each subnet. Fill the following table Subnet Subnet address First host address Last host address Broadcast address 1…Provide short answers to the following: How do you determine whether an IP address is a multicast address? What is the TTL field in the IP header used for? What is the maximum length of options bytes that can be carried in an IPv4 header? Why do we have to multiply the offset field of an IP datagram by eight to obtain the real offset for the first byte of the datagram?
- Suppose the sequence number field on a TCP packet is 46005. The packet carries 102 bytes of (application-layer) data. The TCP header size on this packet is 20 bytes. (a) What is the sequence number of the last application byte contained in the packet above? (b) What is the value of the acknowledgment number field on the ACK that the receiver generates for the packet above? (c) Do you have sufficient information in this question to determine the value of the sequence number field of the ACK packet that the receiver generates for the packet above? If so, what is the sequence number? If not, why not? (d) If the size of the TCP header were larger (e.g., 24 bytes, due to additional TCP options), would your answers to parts (a)–(c) change? Why or why not?TCP sessions are full-duplex, which means that data can be sent in either direction during the lifetime of the session. Consider a session in which the connection is established, the client sends 100 data segments, all of them are ACKed, and all of the ACKS are received by the sender, then the session is ended by both sides closing the connect. How many segments in total have the SYN bit of the header set to 1? а. 4 O b. 2 с. O d. 1 е. 209The first of these packets is from your computer to the DHCP server telling it to release the lease on your IP address. The next 4 packets renew that lease. Note that the source address on the “DHCP Discover” and “DHCP Request” packets is 0.0.0.0. This indicates that your computer does not actually use its new IP address until the interchange has completed. Also note that the destination address in each of the 4 packets is a broadcast address[1]. It should be obvious to you why the first two packets are broadcasted, but what about the last two? Can you explain this? Answer the questions in your Word document right after you post a snapshot of the DHCP packet screen. (#4)
- For a given an IP v4 datagram, with header fields: HLEN - 5. Total length - 2220 and flag field (RDM) - 000. If this datagram is required to pass through a network of MTU - 1164 byte and need to be fragmented, choose the correct answer 1_For the given packet, the header size is 10 bytes 20 bytes 40 bytes 30bytes 2_The number of fragments to which the given packet is fragmented to pass through the network of MTU: 164: three Tour two Six Network Ineed answer after 30 minA 3200 bit long TCP message is transmitted to the IP layer and becomes a datagram after adding a 160 bit header. The following Internet is connected by two LANs through routers. But the data part of the longest data frame that the second LAN can transmit is only 1200 bits. Therefore, datagrams must be segmented in the router. How many bits of data does the second LAN transmit to its upper layer?. Suppose Host A sends over a TCP connection to Host B one segment with sequence number 3777 and 1500 bytes of data. Assuming the segment is received correctly, what is the sequence number of the ACK that Host B sents to Host A for this segment? 2.Calculate the the Internet checksum of 0100 1011 1001 1111 and1100 1100 0101 1101. 3.How many control messages are required to close a TCP connection?
- An IPV4 datagram has arrived with the following information in the first bytes of the header (in hexadecimal): OX4B 04 00 F7 01 05 60 18 10 06.... Answer Questions from (1 to 11) *The size of the options in bytes if available is: What's the number of the third data byte in the original packet? What's the number of the last data byte in the original packet? How many hops this packet can travel before being dropped?Which of the following instructions falls in the category of data transfer instructions? JUMP LOAD ROTATE ANDDraw a NAT Table Entry at the Router for the Computer (A) (shown with a smiley face J) trying to reach the Web Server (listening at Port 80) as shown. You may use dynamic port numbers.