I.Determine the interior angles of each stations and azimuths for each surveying lines.AZAB =INTZA =4040P 37AZBC =INTZB =C30 22AZCD =INTZC =66° 40'AZDE =INTZD =15° 121s° 58AZEA =INTZE =

The azimuth for line AB, AZAB can be written as: AZAB=90°-30°22'=59°38° The azimuth for line BC,…

Answered: I. Determine the interior angles of…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The numerical value of departure equals the difference between the X coordinates of A and B, i.e. the increment AxAB, while the numerical value of latitude equals the difference between the Y coordinates of A and B, i.e. the increment AYAB- grid azimuth The horizontal distance DAB and the AAB can be computed. Ar - Xg - XxA Ay AB = Ys - YA D - Jar, + Ay Ay Ar AB AB = arctan AB AB
30 Y 5OKN 3. 4 40° 7OKN 450 l00 KN z Fy=? ī Fx = ? %3D RF = ? %3D 20
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
FUNDAMENTALS OF SURVEYING Triangulation stations A,B, C and D has the following observation angles. Angle Values ACB 50 deg BAD 20 deg BCD 30 deg ABC 50 deg CAD 60 deg a. Find the angle CDB b. Find the angle BDA c. Find the angle BDC
Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
Given the close traverse survey below, compute for all the adjusted Lengths and Bearings. Show complete solution. PS. Answer to this problem requires a file upload, be sure to upload it here together with your solutions. TY. 58°34 364.55 1. Length () 347.00 364.55 472.74 292.94 Line Azimuth 509 05 38 258 34 22 128 04 44 60 21 26 ST TU •00 UV SHOT ON MI 10T I BY: ALEXIS VS
1Q is 18 7T is 72
Triangulation stations A,B,C and D has the following observation angles. Angles: ACB=50° BAD=20° BCD=30° ABC=50° CAD=60° a. Find the angle CBD. b. Find the angle BDA. C. Find the angle BCD.
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m
Q" shape of flaverse & close Bopen open Traverse typesy=- free open traverse 22-Districted • Pentyaverse Ex: N am F-BABE ||| B 17+55 m) = A = 268 08 Hő B = 273° 55' 40" C= 18° of 40" D = 301⁰ 36 20 O E = 1h6 20 L 17.35m с جمع EQ 26 20 N 13.79m E Scanned with CamScanner
Calculate the interior angles from the following :observations Line PQ QR RS ST TP Bearing S 37° 30' E S 43° 15' W N 73° 00′ W N 12° 45' E N 60° 00' E
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the Area of the Traverse. Line Length Bearing AB 589.060 m N 87°30’ E BC 391.730 m N 07°02’ E CD 291.860 m N 30°30’ E DE 656.980 m S 42°45’ E EF 654.060 m Unknown FA 686.660 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

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I. Determine the interior angles of each stations and azimuths for each surveying lines. AZAB = INTZA = 40 40P 37 AZBC = INT2B = 30 22 AZCD = INTLC = 66 40 D AZDE = INT2D = 15° 12 1S° 58 AZEA = INTZE = E