I-Shinx dx Ig-/sin'xdx 2-x2 dx

Q: √tanx secox dx

A: We know that integration of xn is xn+1/n+1.   Here i attached the solution of this question.

Q: dx sin x tanx

A: Here we have to solve only part b

Q: السؤال 3 -Sec2 (). dx tan (5). · dz O ). de tan tan . da O ). dz O tan

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Q: | (5cotx – sin x) csc² x dx

A: Given integral is: ∫5cotx-sinxcsc2xdx Rewriting the integral:…

Q: (sinºx sec²x csc³x + sin*4x).dx

A: Given an integral. We need to evaluate it.

Q: Find [(x- sin(2x)) dx

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Q: -sin(4x²) = dx

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Q: Je-2x sin 2x dx

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Q: dx 2. 2 - sinx

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Q: sin S S. cossx (3-2secs)

A: The given integral is ∫sin 5xcos2(5x)3-2sec(5x)dx The derivative formula is ddx(sec ax)=atan…

Q: 1³ csc x - sinx 5 sin x -dx

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Q: 2- cusx dx COSX Sinx +2 Sinx t5

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Q: cos(2x) dx sinx+cosx

A: Given: ∫cos(2x)sinx+cosxdx

Q: se*cosx dx e-sinx

A: Let sinx = u then cosxdx = du

Q: 3. dx (sinh(2xV1+x du

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Q: cos x- sin dx 1- sin 2x

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Q: ( 2sinx sin(2x) dx

A: Given,        ∫2sin2xsin(2x)dx

Q: 16. 4x2 sinh (x³) tanh (x³) dx

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Q: Sinx dx Cosx/1-Cos²x S 2*dx

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Q: - Se-3x sin 4x dx

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Q: 1. ( sinhx - sinhx +coshx coshx dx

A: We have to find

Q: | sin³(18x) dx =

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Q: sin3x dx 1+ tanx

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Q: [sinh(x)(x² + 7*)] dx a.

A: As per our guidelines we are supposed to answer only one question i.e. the first question. For the…

Q: 2 dx tan x(5+ln sin x)

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Q: S sin-1 3x dx

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Q: x² sin 2x dx

A: From integration by parts method we know that, ∫udv =uv-∫vdu From given date ∫x2sin2xdx  Let u= x2…

Q: 1. 2. dx dx sin²(x² + 2x + 1) [4 tan(3x³) - 5 csc x]

A: To find derivatives

Q: 5. Ò sin(x- )dx

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Q: | sin´x-cos²x dx

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Q: (5x+sin3(4x) + sin(4x³)) dx

A: use differentiation for finding the solution.

Q: 1-sinx dx 1-sin?x

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Q: y- SinX+ tan x3

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Q: | sin-1 3x dx

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Q: 4-S e²*sinx dx

A: We have to find the integration of the given function.

Q: -22 (sinhx+coshx) dx

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Q: 2e3* sin 2x dx

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Q: -sin xdx

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Q: 4x² sinh (x³) tanh (x³) dx

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Q: cos(2x) dx sinx+cosx dx Vex

A: Find your answer below

Q: 3 y = sin³ 2x

A: We have to use chain rule here.

Q: 5. S sinxtanx-cosxtanx dx sinxsecx(sinx+cosx)-5

A: Dear student, as per our rule we can only solve one question in one session. Please post the other…

Q: Se-Ax .sinh(2x) dx

A: We know, sinh(x)=ex-e-x2

Q: e) y=sin(tanx) f) y = sin³ 7x

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Q: sinx dx /1-x²

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Q: Find: e sinx dx tanx CsC x dx 4x3 + 4x²+ x

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Q: 1 - Sin 2X dx くDSX -sinx

A: We have ∫1- Sin2xCosx - Sinxdx   here the given function can't intigrated directly we need to first…

Q: —2х Se-2x sin 3x dx

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Q: fcox In(sinx) dx= fu du cotx In(sinx) dx = u du

A: In this question we substitute  u=lnsinx .

Q: Evaluate sin(ln æ) dx .

A: