Hydrogen selenide (H2Se) reacts with water according to the following equation. H2Se + H2O → SeH– + H3O+ Can you identify the acid, base, conjugate acid, and conjugate base in this reaction? Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction

Chemistry: The Molecular Science
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Chapter6: Covalent Bonding
Section: Chapter Questions
Problem 85QRT
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Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

Can you identify the acid, base, conjugate acid, and conjugate base in this reaction? Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

ELECTRONEGATIVITY
H
Не
2,1
Li
Be
В
N
F
Ne
2,0 2,5 3,0 3,5 4,0
1,0 1,6
Mg
0,9 1,2
Sc
Na
Al
Si
P
S
CI
Ar
1,5 1,8 2,1 2,5 3,0
Se
0,8 1,0 1,3 1,5 1,6 1,6 1,5 1,8 1,9 1,9 1,9 1,6 1,6 1,8 2,0 2,4 2,8
K
Са
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
Ga
Ge
As
Br
Kr
Rb
Sr
Y
Zr
Nb
Mo
Tc
Ru
Rh
Pd
Ag
Cd
In
Sn
Sb
Te
Хе
0,8 1,0 1,2 1,4 1,6 1,8 1,9 2,2 2,2 2,2 1,9 1,7 1,7 1,8 1,9 2,1 2,5
Os
0,7 0,9 1,0 1,3 1,5 1,7 1,9 2,2 2,2 2,2 2,4 1,9 1,8 1,9 1,9 2,0| 2,1
Cs
Ba
La
Hf
Ta
W
Re
Ir
Pt
Au
Hg
TI
Pb
Bi
Po
At
Rn
low
medium
high
Transcribed Image Text:ELECTRONEGATIVITY H Не 2,1 Li Be В N F Ne 2,0 2,5 3,0 3,5 4,0 1,0 1,6 Mg 0,9 1,2 Sc Na Al Si P S CI Ar 1,5 1,8 2,1 2,5 3,0 Se 0,8 1,0 1,3 1,5 1,6 1,6 1,5 1,8 1,9 1,9 1,9 1,6 1,6 1,8 2,0 2,4 2,8 K Са Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te Хе 0,8 1,0 1,2 1,4 1,6 1,8 1,9 2,2 2,2 2,2 1,9 1,7 1,7 1,8 1,9 2,1 2,5 Os 0,7 0,9 1,0 1,3 1,5 1,7 1,9 2,2 2,2 2,2 2,4 1,9 1,8 1,9 1,9 2,0| 2,1 Cs Ba La Hf Ta W Re Ir Pt Au Hg TI Pb Bi Po At Rn low medium high
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