Hydrogen iodide decomposes according to the reaction 2 HI(g) → H₂(g) + I₂(g) A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of I₂, and 0.0244 mol of HI at 703 K. When equilibrium is reached, the concentration of H₂(g) is 0.00467 M. What are the concentrations of HI(g) and I₂(g)?

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.52QE: Consider 0.200 mol phosphorus pentachloride sealed in a 2.0-L container at 620 K. The equilibrium...
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Hydrogen iodide decomposes according to the reaction
2 HI(g) → H₂(g) + I₂(g)
A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of I2, and 0.0244 mol of HI at
703 K. When equilibrium is reached, the concentration of H₂(g) is 0.00467 M. What are the
concentrations of HI(g) and I₂(g)?
[HI] eq
M
5 attempts left
M
Check my work
Transcribed Image Text:[2leq Be sure to answer all parts. Hydrogen iodide decomposes according to the reaction 2 HI(g) → H₂(g) + I₂(g) A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of I2, and 0.0244 mol of HI at 703 K. When equilibrium is reached, the concentration of H₂(g) is 0.00467 M. What are the concentrations of HI(g) and I₂(g)? [HI] eq M 5 attempts left M Check my work
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