Hydrogen gas and iodine gas react via the following equation. H2(g) + I2 (9) 2 HI(g) K = 79 (at 650 K) If 0.027 mol HI is placed in an empty 1.0 L flask at 650 K, what are the equilibrium concentrations of HI, I2, and H₂? = [H2]eq [12] eq = [HI] eq = M ΣΣ M M

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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Hydrogen gas and iodine gas react via the following equation.
H2(g) + I2 (9) 2 HI(g)
K = 79 (at 650 K)
If 0.027 mol HI is placed in an empty 1.0 L flask at 650 K, what are the equilibrium
concentrations of HI, I2, and H₂?
=
[H2]eq
[12] eq =
[HI] eq =
M
ΣΣ
M
M
Transcribed Image Text:Hydrogen gas and iodine gas react via the following equation. H2(g) + I2 (9) 2 HI(g) K = 79 (at 650 K) If 0.027 mol HI is placed in an empty 1.0 L flask at 650 K, what are the equilibrium concentrations of HI, I2, and H₂? = [H2]eq [12] eq = [HI] eq = M ΣΣ M M
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