Hydrogen and iodine react to form hydrogen iodide, like this: H₂(g) +1₂(g) → 2 HI(g) Use this chemical equation to answer the questions in the table below. Suppose 220. mmol of H₂ and 220. mmol of I₂ are added to an empty flask. How much HI will be in the flask at equilibrium? Suppose 175. mmol of HI are added to an empty flask. How much HI will be in the flask at equilibrium? None. O Some, but less than 440. mmol. O 440. mmol. O More than 440. mmol. None. O Some, but less than 175. mmol. O 175. mmol. O More than 175. mmol.

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Chapter14: Chemical Equilibirum
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Hydrogen and iodine react to form hydrogen iodide, like this:
H₂(g) + I₂(g) → 2 HI(g)
Use this chemical equation to answer the questions in the table below.
Suppose 220. mmol of H₂ and
220. mmol of I₂ are added to an
empty flask. How much HI will be in
the flask at equilibrium?
Suppose 175. mmol of HI are added
to an empty flask. How much HI will
be in the flask at equilibrium?
None.
Some, but less than 440. mmol.
440. mmol.
More than 440. mmol.
None.
Some, but less than 175. mmol.
O 175. mmol.
More than 175. mmol.
X
Ś
Transcribed Image Text:Hydrogen and iodine react to form hydrogen iodide, like this: H₂(g) + I₂(g) → 2 HI(g) Use this chemical equation to answer the questions in the table below. Suppose 220. mmol of H₂ and 220. mmol of I₂ are added to an empty flask. How much HI will be in the flask at equilibrium? Suppose 175. mmol of HI are added to an empty flask. How much HI will be in the flask at equilibrium? None. Some, but less than 440. mmol. 440. mmol. More than 440. mmol. None. Some, but less than 175. mmol. O 175. mmol. More than 175. mmol. X Ś
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