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- Mganga is doing a routine analysis in a copper plating factory. He is regularly making up solutions of verypure CuSO4.5H2O. He suspect that a batch of a reagent used to make up a stock solution of CuSO4.5H2Ois impure and it may contains some CuCl2. He asked you to determine the percentage impurity as follows:Dissolve1.500g of a mixture and make up to 1.00L mark.150mL of this solution was treated with 20.00mLof 0.100M AgNO3 to remove 98.6% of chloride as AgCl precipitate.What is the percentage of organic compound that is dissolved in soil pore water that has a porosity of 0.41 and the Kd = 563 L kg-1 ? Report your answer in percentage and enter it is X.Xx10(-X) or X.Xx10(X)For a 22.16 mg sample of MgC2O4•H2O (Mwt = 130.35 g/mol) shows two steps:a loss of 3.06 mg from 100–250 oC and a loss of 12.24 mg from 350–550oC. For each step, identify the volatilization product and the solidresidue that remains. In second step, two volatile products are formed.(Mwt C = 12 g/mol; O = 16 g/mol; H = 1 g/mol)
- 17- The percentage of protein in meat products is determined by multiplying the %N as determined by the kjeldahl method by the arbitrary factor 6.25. A sample of processed meat scrap weighing 2.000 g is digested with concd H2SO4 and Hg (catalyst) until the N present has been converted to NH&HSO.. This is treated with excess NaOH, and the liberated NH3 is caught in 50.0 mL pipetful H2SO, (1.000 ml 0.01860g NazO). The excess acid requires 28.80 mL NaOH (1.000 mL = 0.1266 g KHP). Calculate % protein in the meat scrap.BC Broward Col x O Onelogin xe Expt. 6 pre-l xA "Expt. 7 Quiz X G .What is an x b ziprecruiter x O 12.628+ Par X E Login x + O File | C/Users/nerbs/Downloads/Expt.%207%20Quiz,%20Part%201.pdf 10 2) If absorptivity (the constant of how much light of a given wavelength the sample absorbs) and path length (how much solution there is for light to pass through) are the same, which is true for a Beer's Law solution? a) its concentration and absorbance are proportional b) its concentration and rate are proportional c) its absorbance and rate are proportional d) the solution is an alcoholic beverageA salt solution (30% Na2CO3) weighing 1ton iscooled to 20C where the salt crystallizes asdecahydrate. What will be the crystal yield ifthe solubility is 21.5 kg anhydrous Na2CO3/100kg water? (assume that 3% of the totalsolution is lost by evaporation)
- The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? OA. Solution A: 0.123 Solution B: 0.463 O B. Solution A: 0.463 Solution B: 0.234 O C. Solution A: 0.123 Solution B: 0.234 O D. Solution A: 0.234 Solution B: 0.463The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463Gravimetric determination of Ksp. Table 1 Trial Volume of solution used (ml) Mass of empty beaker (g) Mass of beaker with solid residue (g) Mass Ca(OH)2 (g) Ksp for Ca(OH)₂= % error = 10mL 92.808g 92.766g 0.042g Determine the mass of dissolved solid that was in the saturated solution. Calculate the molar solubility of the solution (M) using the mass of dissolved solid, the volume of solution used in the analysis, and the molar mass of calcium hydroxide. Substitute the molar solubility into a version of equation 4.1 [Hint: use an ICE table] to determine the Kp. Provide an annotated calculation below: 1
- The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with D water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. Which of the following technique can be used to determine the amount of mercury in the undiluted sample of river water? O A. IR spectroscopy O B. Cold vapor atomic absorption OC. Hydride generation atomic absorption OD. Electrothermal atomic absorption> EL session.masteringchemistry.com MasteringChemistry ROSTER-2019-SPRI-PULLM-CHEM-101 blackboard wsu Google Search MasteringChemistry: HW 8 KHW 8 Applications for Dilution Calculations K8 of8 Dilution as a procedure in analysis We sometimes purposely dilute solutions if the analyte concentrations wavelengths in the visible (and sometimes uitraviolet) range. Based on the dissolved solute's properties, we can quantify that solute's concentration are too high to permit an accurate measurement. For example, a spectrophotometer can measure the amount of light that passes through a sample solution for If the solute's concentration is too high, a relatively small amount of incident light having the wavelength that corresponds to the solute's absorption behavior will less light is absorbed, and the detector in the spectrophotometer can generate more reliable data. reach the dete ctor, which results in an inaccurate measurement (consider the result if you blocked the light with an opaque…(Preparation of 0.1 N HCI solution in 250 ml D.W) Procedure: Preparation of approximately (0.IN) HCI from 37% and 1.2 Sp.g • Calculate the Normality of the concentrated HCl from the law: To prepare (500ml) of 0.IN HCL: NI VI = N2 V2 NI x ? = 0.1 x 500 • Transfer some of distilled water to 500ml volumetric flask and add the calculated volume of conc. HCI. Mix the content thoroughly. Complete to the mark with distilled water and make a label.