Homework Help is Here – Start Your Trial Now!
Math
Statistics
How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o= 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <με Part: 1/4 Part 2 of 4 (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) in the sample size will (Choose one) ▼ the standard error. Part: 2/4 Part 3 of 4 The margin of error would be (Choose one) ▼ since (Choose one) in the confidence level will (Choose one) the critical value zα/2. X (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 3/4 Part 4 of 4 X X (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1? It (Choose one) likely that the mean number of personal computers is less than 1. X

How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o= 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <με Part: 1/4 Part 2 of 4 (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) in the sample size will (Choose one) ▼ the standard error. Part: 2/4 Part 3 of 4 The margin of error would be (Choose one) ▼ since (Choose one) in the confidence level will (Choose one) the critical value zα/2. X (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 3/4 Part 4 of 4 X X (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1? It (Choose one) likely that the mean number of personal computers is less than 1. X

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
See similar textbooks
icon
Related questions
Question
100%
How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o = 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <μ< Part: 1 / 4 Part 2 of 4 The margin of error would be (Choose one) size will (Choose one) the standard error. (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 2 / 4 Part 3 of 4 The margin of error would be (Choose one) since (Choose one) in the confidence level will (Choose one) the critical value z a/2* Part: 3 / 4 since (Choose one) in the sample (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part 4 of 4 X I Ś X X Ś (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1 ? It (Choose one) likely that the mean number of personal computers is less than 1. S Es
Transcribed Image Text:How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o = 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <μ< Part: 1 / 4 Part 2 of 4 The margin of error would be (Choose one) size will (Choose one) the standard error. (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 2 / 4 Part 3 of 4 The margin of error would be (Choose one) since (Choose one) in the confidence level will (Choose one) the critical value z a/2* Part: 3 / 4 since (Choose one) in the sample (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part 4 of 4 X I Ś X X Ś (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1 ? It (Choose one) likely that the mean number of personal computers is less than 1. S Es
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 6 steps with 12 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
SEE MORE TEXTBOOKS