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- Doing genetic analysis it is determined that two parents are heterozygous for two separate unlinked recessive traits (i.e., both parents are heterozygous for both loci). Given this genetic information, what is the probability of their having a child which is homozygous recessive for both traits?Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?Imagine that a couple is planning to have children. The male is heterozygous for Huntington’s disease and homozygous dominant for Tay-Sachs. The female is homozygous recessive for Huntington’s disease and heterozygous for Tay-Sachs. The couple is curious about the possibility and probability of their offspring inheriting Tay-Sachs and/or Huntington’s. For humans, Huntington’s disease is dominant (H) over the “normal” condition (h), and the “normal” condition is dominant (T) over Tay-Sachs (t). Complete a Punnett square for this cross and record the probabilities for genotypes and phenotypes of the offspring as ratios.
- If an individual has a widow's peak, but one of their parents does not, which genotypes are possible? Heterozygous Homozygous dominant Homozygous recessive Unable to determineAttached earlobes is recessive while “Free” earlobes is dominant. Determine the phenotypes for both you and your partner. What genotypic and phenotypic ratios would you expect in your offspring?The achoo syndrome (sneezing in response to bright light) is a dominant trait in humans. Two adults who areheterozygous for the achoo gene have a child. What is the probability that their child is homozygous dominant ORhomozygous recessive for achoo?
- If there is a possibility of four different genotypes in the offspring that result from a dominant-recessive inheritance, and if the couple has four children, would they definitely have children with one expressing each genotype? Explain.The pedigree below shows a family tree for hemophilia, which is a sex-linked recessive disorder. 21 10 11 12 13 14 If individual 14 had a child with a man who has hemophilia what is the probability that any of thei 0% O 25% O 50% O 100%The following pedigree tracks how cystic fibrosis (a recessive disorder) has passed in a family. What is the genotype of the first male (from the left) in the first generation of this pedigree? O O OO NN nn Nn N? = E of R
- As attached, is a pedigree related question. I have a question, is it correct that individual I 1 's phenotype is Ff (heterozygous) whereas individual I 2 is ff (recessive homozygous)? That would mean that the ratio of Widow's Peak: Straight hair(no widow's peak) would be 1:1 ? So the chances of getting a Widow's Peak is 50% ? Is this correct? Am I doing it right.If an individual has a widow's peak, which genotypes are possible? Homozygous recessive Unable to determine Homozygous dominant HeterozygousIf a man heterozygous for widow’s peak (dominant) marries a woman homozygous for continuous hairline (recessive), what are the chances the children will have a widow's peak? What are the chances the children will have continuous hairline?