Hi there. Can you help me understand how to find the molar ratio of NaOH:KHC8H4O4? I am extremely confused and cannot seem to figure out how to work out this problem. Thank you so much. Here is the abstract behind it. Potassium hydrogen phthalate (KHP, KHC8H4O4) is a good primary standard. 20 mL of NaOH was titrated with 0.600 M KHC8H4O4 solution. The data was graphed and the equivalence point was found when 15.5 mL of the standard 0.600 M KHP solution was added. The reaction equation is: NaOH (aq)+KHC8H4O4(aq)--> KNaC8H4O4(aq)+H2O

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