Given the initial value problem 2 y y' + = 0, y(0) = 28, y'(0) = b, 5 25 Find the solution as a function of b, and then determine the critical value of b that separates solutions that remain positive for all t > 0 from those that eventually become negative. NOTE: Use t as the independent variable. y" - y(t): = The critical value of b is

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
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Given the initial value problem
Y
25
Find the solution as a function of b, and then determine the critical
value of b that separates solutions that remain positive for all t > 0
from those that eventually become negative.
NOTE: Use t as the independent variable.
y".
-
y(t)
2
=
y' +
=
= 0, y(0) = 28, y'(0) = b,
The critical value of b is
Transcribed Image Text:Given the initial value problem Y 25 Find the solution as a function of b, and then determine the critical value of b that separates solutions that remain positive for all t > 0 from those that eventually become negative. NOTE: Use t as the independent variable. y". - y(t) 2 = y' + = = 0, y(0) = 28, y'(0) = b, The critical value of b is
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