Given the following find: The reactive power dissipated by the source is (in Vars) The apparent power dissipated by the source is (in VA)

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Given the following find:

  1. The reactive power dissipated by the source is (in Vars)
  2. The apparent power dissipated by the source is (in VA)
Solution:-
1Ω
i
is (4
2Ω
0.2 H
1:- Order of the circuit is
1
Answer
element
ckt
having
only
one emengy
stoving
3:-
X = ?
%3D
is = losa cos (377t) Amp
is = Im cos (wt)
Companing
Im= 10VR A b w =377 Y/ke
X = WL = 377X 0.2 = 75.4
%3D
%3D
X = 75.4 2
Answer
is yms
VR
3:-
Im
Asyms
|0 Amp
Answer
ww
Transcribed Image Text:Solution:- 1Ω i is (4 2Ω 0.2 H 1:- Order of the circuit is 1 Answer element ckt having only one emengy stoving 3:- X = ? %3D is = losa cos (377t) Amp is = Im cos (wt) Companing Im= 10VR A b w =377 Y/ke X = WL = 377X 0.2 = 75.4 %3D %3D X = 75.4 2 Answer is yms VR 3:- Im Asyms |0 Amp Answer ww
4:- By C. D-R -
2
lyms =
As Yms
2+Itj75-4,
i yms =
drms = 0.2650-87-7R
Tirms|= 0•2650 Amp
1Ω
5:-
i
Vs
2Ω
0.2 H
(iyms) (I+ j75.4) = (0-2650/-87.72)(1+ j75.4)
Vs 19.9859 /I-5186 Volts
Yms
Vs yms
6 = 1. 5 186°
Ref
ds rms
p.f= cor0 = co3(1.5186")
p.f= 0.9996 (lag)
(6) Palisipated
= 19.9859 X0-2650 X0.9996
Podiss
5. २9५२ Waus
Transcribed Image Text:4:- By C. D-R - 2 lyms = As Yms 2+Itj75-4, i yms = drms = 0.2650-87-7R Tirms|= 0•2650 Amp 1Ω 5:- i Vs 2Ω 0.2 H (iyms) (I+ j75.4) = (0-2650/-87.72)(1+ j75.4) Vs 19.9859 /I-5186 Volts Yms Vs yms 6 = 1. 5 186° Ref ds rms p.f= cor0 = co3(1.5186") p.f= 0.9996 (lag) (6) Palisipated = 19.9859 X0-2650 X0.9996 Podiss 5. २9५२ Waus
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