Given the following equilibrium constants at 417°C,Naz0(s) + 2Na (1) + — О2(9) К, — 3 х 10 2-251NaO(g) = Na(1) +O2(9)2К, — 4х 10 5Naz O2 (s) = 2 Na(1) + O2 (9)NaO2 (s) = Na(1) + O2(g)K3 = 6 x 10-29K4 = 3 x 10-14determine the values for the equilibrium constants for the following reactions:1a. Naz 0(s) +02(9) = Na2O2(s)Equilibrium constantb. NaO(g) + Naz O(s) = NazO2(s) + Na(1)Equilibrium constant =c. 2 Na0(g) = Naz O2 (s)с.Equilibrium constant =(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

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Given the following equilibrium constants at 417°C, Na20(s) = 2 Na(1) + 02 (9) K1 = 3 x 10-2 1 NaO(g) = Na(1) + O2(9) 2 K2 = 4 x 10-5 Naz O2 (s) = 2 Na(1) + O2 (9) NaO2 (s) = Na(1) + O2(g) K3 = 6 x 10-2 K4 = 3 x 10-14 determine the values for the equilibrium constants for the following reactions: 1 a. Naz 0(s) + O2(g) = NazO2 (s) Equilibrium constant = b. NaO(g) + Naz O(s) = NazO2(s) + Na(1) Equilibrium constant = c. 2 Na0(g) - Na2 O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Given the following equilibrium constants at 417°C, Na20(s) = 2 Na(1) + 02 (9) K1 = 3 x 10-2 1 NaO(g) = Na(1) + O2(9) 2 K2 = 4 x 10-5 Naz O2 (s) = 2 Na(1) + O2 (9) NaO2 (s) = Na(1) + O2(g) K3 = 6 x 10-2 K4 = 3 x 10-14 determine the values for the equilibrium constants for the following reactions: 1 a. Naz 0(s) + O2(g) = NazO2 (s) Equilibrium constant = b. NaO(g) + Naz O(s) = NazO2(s) + Na(1) Equilibrium constant = c. 2 Na0(g) - Na2 O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section12.2: The Equilibrium Constant

Problem 12.2PSP: When carbon dioxide dissolves in water it reacts to produce carbonic acid, H2CO3(aq), which can...

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