Given the array A=[3,7,-4,12;-5,9,10,2;6,13,8,11;15,5,4,1], what instruction is needed to create the following array from A, a. B=[-5,10;6,8] b. C=[3;-5;6]
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- # //Write the assembly for the following loop# // Use indexed array access (no pointers)# const int AMAX = 15;# int A[] = {0,1,2,3,4,5,6,7,8,9,10,,11,12,13,14,15};# for (int i=AMAX; i > 0; i--) {# A[i-1] = A[i] * 2;.dataA: .word 0,1,2,3,4,5,6,7, .word 8,9,10,11,12,13,14,15AMAX: .word 15 .text.globl mainmain: #TODO: write the loop code: A[i+1] = A[i] * 2The array sum function below is called on an array of length four starting at address B. List, in order, the data addresses referenced by this function during execution. add1: add $v0, $0, $0beq1: beq $a1, $0, jr1addi1: addiu $a1, $a1, -1lw1: lw $t0, 0($a0)add2: add $v0, $v0, $t0addi2: addiu $a0, $a0, 4beq2: beq $0, $0, beq1jr1: jr $raASSEMBLY LANGUAGE CODE 80x86 only Using the windows32 or windows64 framework, write a program that inputs a collection of integers into an array of doublewords and then sequentially searches for values stored in the array. Implement the following design.
- In C++, Can you please look at the code below and revise/fix so it will work according to instructions and criteria. Instruction 1) Write a function that copies a 1D array to a 2D array. The function’s prototype is bool copy1DTo2D(int d1[], int size, int d2[][NCOLS], int nrows); where size > 0 NCOLS > 0 nrows > 0 NCOLS is a global constant size = NCOLS * nrows the function returns true if the parameters and constants satisfy these conditions and false otherwise. the relation between 1d array indices and 2d array indices is 2d row index = 1d array index / NCOLS 2d column index = 1d array index modulus operator NCOLS 2) Write a function that copies a 2D array to a 1D array. The function’s prototype is bool copy2DTo1D(int d2[][NCOLS, int nrows, int d1[], int size); where size > 0 NCOLS > 0 nrows > 0 NCOLS is a global constant the function return true if the parameters and constants satisfy these conditions and false otherwise. the relation between 1d array indices and…# //Write the assembly for the following loop # //Use indexed array access (no pointers) 15; const int AMAX # # # # . data A: int A[] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}; for (int i=AMAX; i > 0; i--) { A[i-1] = A[i] * 2; } # DO NOT CHANGE THIS TEST DATA .word 1, 2, 3, 5, 6, 7, 4, 9, 10, 11, 12, 13, 14, 15 .word AMAX: . word 15 .text .globl main $t0, AMAX $s0, A #TODO: Write the loop code: A[i+1] = A[i] * 2 main: #highest index #&A[0] lw la loоp: exit: li $v0, 10 syscallProblem: Write a program with a loop and indexed addressing that calculates the sum of all the gaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order. So, for example, the array {0, 2, 5, 9, 10} has gaps of 2, 3, 4, and 1, whose sum equals 10.
- ONE-DIMENSIONAL ARRAY Instruction: There are two lists of numbers. Create a resultant list whose elements are the produc of the elements of the two lists. Example: List A 21 List B 30 List C 630 500 50 10 Write a Java program using a one-dimensional array that accepts as input an integer value asking for the number of elements for each list. This will be used to generate random numbers (10 to 99) for the one-dimensional arrays (List A and List B). The program will compute for the product and store it in another array (List C). Display the result similar to the Example above. Sample Input/Output: Depicted below are sample outputs when the program is executed (the items in bold characters are input from the user, while the items in bold italic are generated, calculated and printed by the program): Input the number of elements: 3 List A 21 50 List B 30 10 List C 630 500 25 10 250 Input the number of elements: 5 List A 31 21 50 60 25 List B 13 30 10 41 10 List C 403 630 500 2460 250Write a complete program in x86 assembly language with irvine package that: 1. Prompt the user to enter 10 numbers. 2. save those numbers in a 32-bit integer array. 3. Print the array with the same order it was entered. 3. Calculate the sum of the numbers and display it. 4. Calculate the mean of the array and display it. 5. Rotate the members in the array forward one position for 9 times. so the last rotation will display the array in reversed order. 6. Print the array after each rotation. check the sample run. ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; Don't use any shift or rotate instructions which we have not coveredyet. You need to use loops and any kind of addressing. All you work should be on the original array. Don't make a copy of the array at any time. Add comments to make your program easy to read. Sample Run: Please enter a number: 2Please enter a number: 3Please enter a number: 4Please…Input array is :- array([[ 1960, 54211], [ 1961, 55438], [ 1962, 56225], [ 1963, 56695], [ 1964, 57032], [ 1965, 57360], [ 1966, 57715], [ 1967, 58055], [ 1968, 58386], [ 1969, 58726], [ 1970, 59063], [ 1971, 59440], [ 1972, 59840], [ 1973, 60243], [ 1974, 60528], [ 1975, 60657], [ 1976, 60586], [ 1977, 60366], [ 1978, 60103], [ 1979, 59980], [ 1980, 60096], [ 1981, 60567], [ 1982, 61345], [ 1983, 62201], [ 1984, 62836], [ 1985, 63026], [ 1986, 62644], [ 1987, 61833], [ 1988, 61079], [ 1989, 61032], [ 1990, 62149], [ 1991, 64622], [ 1992, 68235], [ 1993, 72504], [ 1994, 76700], [ 1995, 80324], [ 1996, 83200], [ 1997, 85451], [ 1998, 87277], [ 1999, 89005], [ 2000, 90853], [ 2001, 92898], [ 2002, 94992], [ 2003, 97017], [ 2004, 98737], [ 2005, 100031], [ 2006, 100832], [ 2007, 101220], [ 2008, 101353], [ 2009, 101453], [ 2010, 101669], [ 2011, 102053], [ 2012, 102577], [ 2013, 103187], [ 2014, 103795], [ 2015, 104341], [ 2016, 104822], [ 2017, 105264]]) Question 2 Now that…
- Write a C program which initially creates 2 two-dimensional integer arrays: arrayA and arrayB. The size of the arrays should be 4 x 4. The program should use scanf() to take an integer test input (x). The program should then create and print array A and array B as shown: array A [x, 2х, 3х, 4х, 2х, 4х, 6х, 8х, Зх, 6х, 9х, 12х 4х, 8х, 12х, 16х] Array B [2х, 3х, 4х, 5х, 4х, 6х, 8х, 10х, 6х, 9х, 12х, 15х, 8х, 12х, 16х, 20х] The program should then create and print new arrays for each of the following situations: · An array containing the sum of corresponding cells in arrayA and arrayB · An array containing the sum of corresponding rows in arrayA and arrayB • An array containing the sum of corresponding columns in arrayA and arrayB Note: Please include exactly one space after each element in each array (including the last one), each row on a new line, and exactly one blank line after each array as shown in the example. For example: Input Result 2 2 4 6 8 4 8 12 16 6 12 18 24 8 16 24 32 4 6…Given a = 10, b = 5, c = 3 and the array arr[1:5] = [ 9 6 8 5 7], whatdoes the following pseudo-code do to the array arr and the variables a, b, c?for i = 1 to 5 arr[i] = a a = b b = c c = arr[i]endMIPS Assembly The program: Write a function in MIPS assembly that takes an array of integers and finds local minimum points. i.e., points that if the input entry is smaller than both adjacent entries. The output is an array of the same size of the input array. The output point is 1 if the corresponding input entry is a relative minimum, otherwise 0. (You should ignore the output array's boundary items, set to 0.) My code: # (Note: The first/last entry of the output array is always 0# since it's ignored, never be a local minimum.)# $a0: The base address of the input array# $a1: The base address of the output array with local minimum points# $a2: Size of arrayfind_local_minima:############################ Part 2: your code begins here ###la $t1, ($t2)la $t1, ($t2)move $a1, $s0 li $a2, 4jal find_local_minima print:ble $a2, 0, exitlw $a0, ($s0)li $v0, 1syscall addi $s0, $s0, 4addi $a2, $a2, -1 ############################ Part 2: your code ends here ###jr $ra I am not getting the correct…