Given thatfind the Laplace transform of ✓cos (8t)√ cos(8t)} = (-16)^(-8/s) (88 (5/8))Preview My AnswersSubmit AnswersC{cos(8t)mt}

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Answered: Given that find the Laplace transform…

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter4: Calculating The Derivative

Section4.5: Derivatives Of Logarithmic Functions

Problem 51E

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Find the inverse transform of the equation below. V(s) = (1-3s) / (s^2+8s+21) A [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(-4t)] + [3*cos(sqrt(5)t)*e^(-4t)] B [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(-4t)] - [3*cos(sqrt(5)t)*e^(-4t)] C [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(4t)] - [3*cos(sqrt(5)t)*e^(-4t)] [(13*sqrt(5)/5)*cos(sqrt(5)t)*e^(-4t)] - [3*sin(sqrt(5)t)*e^(-4t)] E [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(4t)] - [3*cos(sqrt(5)t)*e^(4t)] [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(-4t)] - [3*cos(sqrt(5)t)*e^(4t)]
Find the inverse transform of the equation below. V(s) = (1-3s) / (s^2+8s+21) [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(-4t)] - A [3*cos(sqrt(5)t)*e^(4t)] [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^{-4t)] - В [3*cos(sqrt(5)t)*e^{-4t)] [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(4t)] - [3*cos(sqrt(5)t)*e^{(4t)] [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(-4t)] + D [3*cos(sqrt(5)t)*e^(-4t)] [(13*sqrt(5)/5)*cos(sqrt(5)t)*e^(-4t)] - E [3*sin(sqrt(5)t)*e^(-4t)] [(13*sqrt(5)/5)*sin(sqrt(5)t)*e^(4t)] - F [3*cos(sqrt(5)t)*e^(-4t)]
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(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)
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Given that find the Laplace transform of √cos (8t) C{√/cos(8t)} = (-16)^(-8/s)/(88 (5/8)) CL cos(8t) Vat