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- Calculate the percentage CH3COOH in a sample of vinegar from the following data.Sample = 15.00 g, NaOH used = 43.00 ml ; 0.600 N H2SO4 used for back titration =0.250 ml ; 1.00ml NaOH is equivalent to 0.0315 g H2C2O4. 2H2O.0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. What is the molar concentration required?Questions 11-14 refer to the same strong base/strong acid (SB/SA) titration. A 15.00 mL solution of 0.100 M sodium hydroxide (NaOH) is being titrated with 0.250 M hydrobromic acid (HBr). What is the total solution volume (in mL) at the equivalence point? (Nearest whole number) Type your answer...
- Calculate the pHpH of the solution that results from each of the following mixtures. a)55.0 mLmL of 0.17 molL−1 HCOOH(Ka=1.8×10−4) with 70.0 mLmL of 0.13 molL−1molL−1 HCOONa b)120.0 mLmL of 0.13 molL−1molL−1 NH3NH3 (Kb=1.76×10−5Kb=1.76×10−5) with 240.0 mLmL of 0.13 molL−1molL−1 NH4ClNH4ClAn analyst was titrating a solution of unknown acetic acid concentration with 0.01 M NaOH using phenolphthalein as indicator. After adding exactly 39.4 ml of the titrant drop-wise, the analyte solution started to turn light pink. The titrant volume 39.4 ml is best referred to as the O equivalence point. Onone of the choices O standardization point. O equilibrium point. O endpoint.1. You will use 0.5mM PNPP, 0.2M Tris-HCl, and 1mM P; stock solutions to prepare two sets of five samples (Sets A and B), each with varying P; concentrations. The PNPP concentration for all samples in Set A will be 0.05mM; and 0.150mM for all samples in Set B. Fill out the tables below and use them to prepare your samples. Be aware of the following: • Prepare the samples directly in cuvettes. Prepare one sample at a time to minimize exposing PNPP to air. You can prepare the next sample while the current one is being measured. • Each sample before adding enzyme (i.e., the cuvette only contains PNPP, Pi, and Tris-HCI) is its own blank. In other words, you add the appropriate amounts of PNPP, Pi, and Tris- HCI to a cuvette, press "Measure Blank", then add 100μL of AP to the same cuvette, mix, and press "Measure Sample". • You must blank the instrument (before adding the enzyme) each time you prepare a new sample. Table 1. Sample Set A (PNPP concentration = 0.05mM) Final [Pi] (μM) Vol of…
- Be sure to answer all parts. From the solubility data given, calculate the solubility products for the following compounds. (a) SrF2, 7.3 × 10-² g / L: x 10 Enter your answer in scientific notation. (b) Ag3PO4, 6.7 × 10-3 g / L: x 10 Enter your answer in scientific notation.How many mL of 0.112M Pb(NO3)2 are needed to completely react with 25.0mL of 0.105M KI? Given: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3.a. 11.7b. 23.4c. 0.147d. 5.850.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point.
- It is found that 24.68 mL of 0.1165 M NaOH is needed to titrate 0.2931 g of an unknown acid to the phenolphthalein end point. Calculate the equivalent mass of the acid.Calculate the percentage CH3COOH in a sample of vinegar from the following data. Sample = 15.00 g, NaOH used = 43.00 ml ; 0.600 N H2SO4 used for back titration =0.250 ml ; 1.00 ml NaOH is equivalent to 0.0315 g H2C2O4. 2H2O.10. A 0.514 gram sample of NazCO, (106.0 g/mol) was dissolved in distilled water in a 100.0 mi volumetric flask. The molar concentration of Na,CO, in solution is: 0.0485 M 0.0370 M b. 0.4849 M 0.0340 M 0.0330 M d. е.