Given: Find: A 0.5-inch diameter pole (L1-12 in, L2= 22 in) is loaded with three forces (two forces of P₁ = 2.5 kip and one force of P2 = 7 kip). The pole is made of copper with a modulus of elasticity of 14.5x10³ What is the final length of the pole after the loading is applied? Provide you answer to 0.01 inches. L₁ in B P₁ kip P₁ kip L₂ in P₂ kip

Given: Find: A 0.5-inch diameter pole (L1-12 in, L2= 22 in) is loaded with three forces (two forces of P₁ = 2.5 kip and one force of P2 = 7 kip). The pole is made of copper with a modulus of elasticity of 14.5x10³ What is the final length of the pole after the loading is applied? Provide you answer to 0.01 inches. L₁ in B P₁ kip P₁ kip L₂ in P₂ kip

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when one end is twisted through an angle of 30°, what must be the length of the bar in m? modulus of rigidity=80 GPa . (close to two decimal)
A round steel bar with a diameter of 1.500 in is subjected to the axial loads shown. P1 = 95 k, P2 = 115 k, P3= 55 k, P4 = (P1-P2+P3) k. If Section 2 has a length, L2 = 65 inches, find the change in length of Section 2. Report the answer below in inches, absolute value, 3 significant digits. P1 Your Answer: 100 inches Round Steel Bar P2 Section 2 12 P3 80 inches P4
You are given a square rod of 6061-T6 aluminum (cross-section = 4mm X 4mm, length = 2.3m). The material has a Young’s modulus of 72 GPa. If a tensile load of 3 kN is applied parallel to the 2.3m dimension, what is the change in length of the rod?
Q1: An Iron bar has a length of 50 m when the temperature is (-20 "C) .what is the length of the bar in a summer day when the temperature is (38 C) ?Calculate the thermal stress set up in the bar on summer day.a=12 x10 C ,E=25x10 Pa.
Compound axial member ABC has a uniform diameter of d-2.4 in. Segment (1) is an aluminum [E₁ - 10,000 ksi] alloy and segment (2) is a copper [E₂ - 17,000 ksi] alloy. The lengths of segments (1) and (2) are L₁ - 78 in. and L₂ - 150 in., respectively. Determine the force P required to stretch compound member ABC by a total of 0.35 in. L₁ A Part 1 Aluminum Answer: A- B Save for Later Calculate the cross-sectional area of the compound member. L2 (2) Copper in.² C P Attempts: 0 of 1 used Submit Answer Part 2 The parts of this question must be completed in order. This part will be available when you complete the part above. Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above.
The simply supported beam is subjected to the loads as described in the figure and parameter table. Neglecting the thickness of the beam, calculate the horizontal and vertical support reactions at A. F, F2 parameter value units L L2 L3 1.75 ft 1.5 ft 2 ft 30 70 F1 F2 lb 6 lb For the answers, take to the right, up, and counterclockwise to be the positive directions. The horizontal support reaction is lb The vertical support reaction is lb The moment support reaction is lb-ft
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 48512-Nload, using the following data: length of steel = 1.42 m, length of bronze = 2.36 m Area of steel = 639 mm, Area of bronze = 319 mm Modulus of elasticity of steel = 180 Gpa, Modulus of elasticity of bronze = 81 Gpa x = 0.58 m, y = 1.13 m, and z = 0.72 m. Round off the final answer to two decimal places.
HAB A В µCG µBC If the picture does not load, click here. Three blocks are positioned on an incline of 0=24° as shown. A force of P is applied to Block C and a wire attaches Block A to the wall, preventing that block from moving. The mass of Block A is ma=35kg, the mass of Block B is mg=53kg, and the mass of Block C is mc-47kg. The coefficient of static friction between Block A and Block B is UAB=0.18, between Block B and Block C is uBc=0.28, and between Block C and the ground is ucG=0.40. Determine the maximum value of P before any slipping takes place. Write your answer for P in N units to 2 decimal places in the box below. Hint #1: Recall that the shear (tangential) force across a sliding surface can never exceed F = mu * N Hint #2: You will need to find a value for P based on the condition that one block slips AND a value for P based on the condition that multiple blocks slip. The final answer will be the lesser of the two values. Values: HAB=0.18 0=24° ma=35kg HBC=0.28 mB=53kg…
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 45846-Nload, using the following data: length of steel = 11 m, length of bronze = 2.3 m Area of steel = 562 mm, Area of bronze = 335 mm Modulus of elasticity of steel = 195 Gpa, Modulus of elasticity of bronze = 80 Gpa x= 0.55 m, y = 1.12 m, and z = 0.78 m. Round off the final answer to two decimal places. ... Bronze Steel
A bar, 12 mm in diameter is acted upon by an axial load of 20 kN. The change in diameter is measured as 0.03 mm. DeterminePoisson’s ratioYoung’s modulusBulk modulus Assume modulus of rigidity as 80 GPa
A 2.25 m long solid bar (Lo) with a 32 mm diameter is placed under tension by a load (F) of 250 kN. The bar is solid and made of a homogeneous material with a Young’s Modulus E = 250 GPa. Calculate the extension of the bar (△L). Give your answer in millimeters (mm) to two decimal places.
The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 43091-Nload, using the following data: length of steel = 1.36 m, length of bronze = 2.08 m Area of steel = 562 mm, Area of bronze = 243 mm Modulus of elasticity of steel = 215 Gpa, Modulus of elasticity of bronze = 102 Gpa x = 0.63 m, y = 1.01 m, and z = 0.84 m.