Given a standard normal distribution, find the areas in part (a) through (f) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Find the area under the curve that lies to the left of z = -1.43. The area is (Round to four decimal places as needed.) (b) Find the area under the curve that lies to the right of z = 1.81. The area is (Round to four decimal places as needed.) (c) Find the area under the curve that lies between z = -2.17 and z = -0.79.
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- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d) between -zand z, with z> 0, is 0.9500. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.Price_($000)/Sq Ft 1/Sq Ft Location 14.0542 0.0653 0 17.2907 0.0524 0 18.3029 0.00649 0 15.7341 0.04374 0 14.8521 0.01913 0 15.3572 0.0197 0 18.3278 0.01583 0 15.8483 0.41563 0 17.392 0.29976 0 15.8826 0.1798 0 15.5492 0.00816 0 14.619 0.0325 0 15.7633 0.21829 0 15.1289 0.015939 0 17.2874 0.18765 0 15.6938 0.00986 0 15.3672 0.03096 0 15.3126 0.01917 0 17.4008 0.06055 0 16.1066 0.0611 0 16.6637 0.1171 1 16.5504 0.05552 1 17.0575 0.00657 1 17.9466 0.1407 1 17.8913 0.0648 1 15.5396 0.03339 1 18.6629 0.03443 1 18.0774 0.019 1 20.8122 0.20162 1 18.3237 0.319 1
- Determine the area under the standard normal curve that lies to the left of (a) Z=1.64, (b) Z=0.14, (c) Z=-1.61, and (d) Z=0.04. Click the icon to view a table of areas under the normal curve. (a) The area to the left of Z= 1.64 is (Round to four decimal places as needed.) View an example Get more help - OLDC Tables of Areas under the Normal Curve (7 -0.0 0.0 -KI U.4002 04302 UA322 0.4483 0.4493 09404 04304 UA32J UAZOO URAT 0.5000 0.4960 0.4920 0.4880 0.4880 0.4840 0.4801 0.4761 0.4721 0.4681 0.4641 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 05239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 05557 0.5596 0.5636 0.5675 05714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454…9. A simple random sample of size n is drawn. The sample mean, x, is found to be 18.3, and the sample standard deviation, s, is found to be 4.8. 15 Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about µ if the sample size, n, is 35. ; Upper bound: (Use ascending order. Round to two decimal places as needed.) Lower bound: (b) Construct a 95% confidence interval about µ if the sample size, n, is 61. Lower bound: Upper bound: (Use ascending order. Round to two decimal places as needed.) How does increasing the sample size affect the margin of error, E? O A. The margin of error decreases. O B. The margin of error does not change. C. The margin of error increases. (c) Construct a 99% confidence interval about u if the sample size, n, is 35. ; Upper bound: (Use ascending order. Round to two decimal places as needed.) Lower bound: Compare the results to those obtained in part (a). How does increasing the level of confidence affect…Areas under the Normal Curve Areas under the Normal Curve z .00 .01 -3.4 0.0003 0.0003 0.0003 0.0003 -3.3 0.0005 0.0005 0.0005 0.0004 -3.2 0.0007 0.0007 0.0006 0.0006 -3.1 0.0010 0.0009 0.0009 0.0009 -3.0 0.0013 0.0013 0.0013 0.0012 -2.9 0.0019 0.0018 0.0018 0.0017 -2.8 0.0026 0.0025 0.0024 0.0023 -2.7 0.0035 0.0034 0.0033 0.0032 -2.6 0.0047 0.0045 0.0044 0.0043 -2.5 0.0062 0.0060 0.0059 0.0057 -2.4 0.0082 0.0080 0.0078 0.0075 -2.3 0.0107 0.0104 0.0102 0.0099 .02 .03 .05 .04 .06 .07 0.0003 0.0003 0.0003 0.0003 0.0004 0.0004 0.0004 0.0004 0.0006 0.0006 0.0006 0.0005 0.0008 0.0008 0.0008 0.0008 0.0012 0.0011 0.0011 0.0011 0.0016 0.0016 0.0015 0.0015 0.0023 0.0022 0.0021 0.0021 0.0031 0.0030 0.0029 0.0028 .08 .09 0.0003 0.0002 -3.4 0.0004 0.0003 -3.3 0.0005 0.0005 -3.2 z Z .00 .01 .02 .03 .04 .05 .06 .07 0.0007 0.0007 -3.1 0.0010 0.0010 -3.0 0.3 0.4 -0.3 0.3821 0.3783 0.3745 2 .00 .01 0.0041 0.0040 0.0039 0.0038 0.0055 0.0054 0.0052 0.0051 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.4…
- Areas under the Normal Curve .00 .01 .02 .01 .02 .03 .04 .05 .06 .07 .08 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 -3.4 -3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 -3.3 -3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 -3.2 -3.1 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 -3.1 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 -3.0 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.9 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.8 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.7 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.6 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.5 -2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.4 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094…= okil Determine the area under the standard normal curve that lies to the right of (a) Z= -0.63, (b) Z=0.93, (c) Z=0.31, and (d) Z= -0.72. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) The area to the right of Z= -0.63 is (Round to four decimal places as needed.) 150 O E 4 a de Clear all 73°F Sunny2.THEORY OF DISTRIBUTIONS