Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0 A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes (x')^2/4 - (y')^2 = 1 Find the vertices of the conic in the xy-plane

Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0 A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes (x')^2/4 - (y')^2 = 1 Find the vertices of the conic in the xy-plane

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter11: Topics From Analytic Geometry

Section: Chapter Questions

Problem 25RE

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Question

Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0

A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes

(x')^2/4 - (y')^2 = 1

Find the vertices of the conic in the xy-plane

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