Give the time complexity of the following method. void method1(int n) { } for (int i = n; i >= 1; i--) { } for (int j = n; j >= 1; j -= i) { System.out.println("*"); } Write Theta, O, or Omega for the symbol. Symbol: Write the function g(n), as in: n^2 n lg n n^(5/2) Function =
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- public static int Ack(int m, int n) { if (m == 0) { return n + 1; } else if (n == 0) { return Ack (m } else { } } return Ack (m - - 1, 1); 1, Ack (m, n- What is the return value of this function for a. Ack(0,0) b. Ack(0,3) c. Ack(0,6) Can you use the above three samples and come up with a formula for Ack(0,n)? 1));Write a Java program that includes in its class the following methods:- A method named unitMatrix which takes one parameter which is an integer (n) and - prints a unit matrix of dimension (nxn). A unit matrix is a square matrix in which the - diagonal elements are all 1s and the remaining elements are 0s.- For example for n = 3 the printed unit matrix should be:- 1 0 0 - 0 1 0- 0 0 1- - A method named triangularMatrix which takes two parameters. The first parameter is - an integer (n) which specifies the dimensions of the triangular matrix to be printed - (nxn). The second parameter is a boolean which specifies the type of the triangular - matrix: if its value is true, the printed matrix must be an upper triangular matrix- (square elements with all elements below the diagonal are 0s), if its value is false the - printed matrix must be a lower triangular matrix (square elements with all elements - above the diagonal are 0s). - The values of non-zero elements must start…The following is a implementation of the Ackermann function: public static long Ackermann(int m, int n){ 0) return n + 1; if (m == else if (n == return Ackermann(m 1, 1); else return Ackermann(m 1, Ackermann(m, n - 1));
- int getMax(int arr[], int n) { intmx=arr[0]; for (inti=1; i<n; i++) if (arr[i] >mx) mx=arr[i]; returnmx; } Can u give me the code for this one as well....this is the first function and countsort is the secondWrite a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Given the f() method below. rewrite the method by making use of lambda expression. int f(int a, int b){ } return a + b; UnaryOperator f = (a, b) -> a + b; Function f = (a, b) -> a + b; Function> f = (a, b) -> a+b; BinaryOperator f = (a, b) -> a + b;
- Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…Consider the following method, written in pseudocode: function recur(n): if n <= 10 then return n * 2 return recur( recur( floor(n / 3) ) ) What does recur(35) return?Solve the following problem by writing methods/functions A) Write a method int sum (int, int) with takes 2 parameter as an input to the function and return the sum of these numbers(negative or positive) , to the calling function by using recursion g. sum (6, 5 ) return 11 sum (-4, 3) return -1 sum (-3, -4 ) return -7 B) Write a method age (i) which takes input age in numbers of days as a parameters print the age in years and month Age (3750) will print 10 years, 3 months Solve with C#
- inhinclude Rsing namespace std; int maxResult( ) int maxVal for (int i { for (int j = 0; j <= n 0; i <= n; i += a) i; j += b) %3D %3D float z = (float)(n (i + j)) / (float)(c); if (floor(z) { int x = int y ceil(z)) i / a; j/ b; maxVal = max(maxVal, x + y (int)z); return maxVal; } int main() { max cout << maxResult( ); return 0; 1 } Input Compilation failed due to fellowing ons main.cpp:7:23: error: 'n' was not declared in this scope 7| for (int i = 0; i <= n; i a) main.cpp:7:31: error: 'a was not declared in this scope for (int i = 0; i <= n; i t= a) %3D main.cpp:9:36: error: b' was not declared in this scope | 6 for (int j = 0; j <= n - i; j - b) %3D main.cpp:11:45: error: 'c was not declared in this scopePlease Program this in SMALLTALK Extend class Array with the method contains:. It returns true if the argument is in the array, and false if not. Use the #= binary message for comparisons. Example interaction: st> a := #(3 1 4 8 7 3). (3 1 4 8 7 3 ) st> a contains: 4. true st> a contains: 99. false Start of answer: Array extend [Write a recursive method that takes as parameter as array of type double (num) and the length of the array (len). The method should display the square root of numbers that are greater than 10.0 in the array. The method prototype is: public static void display(double [] num, int len); You may use sqrt method that is defined in the Math class.